Dimension problem in for loop?

I have problem with dimensions. Please find the whole code in attachment.
clc;
clear all;
close all;
format long g;
load('Data\data.mat')
X_1 = reshape(transpose(coord{1:4,2:3}),[8,1]);
X_2 = reshape(transpose(coord{5:8,2:3}),[8,1]);
posteriori_standard_deviation = 1.02; %in meter
displacement_vector = [X_2-X_1];
F = [1 0 1 0 1 0 1 0]%; 0 1 0 1 0 1 0 1];
n=4;
x_gravity_epoch1 = (1/n)*(F* X_1);
x_gravity_epoch2 = (1/n)*(F* X_2);
X1_bar_i = X_1 - x_gravity_epoch1';
X2_bar_i = X_2 - x_gravity_epoch2';
% x_bar_i = x_bar_i';
% y_bar_i = y_bar_i';
for i=1:size(X1_bar_i)
H(i,:)= [0 X1_bar_i(i+1,1) X1_bar_i(i,1) -X1_bar_i(i+1,1) 0 1;X1_bar_i(i+1,1) X1_bar_i(i,1) 0 X1_bar_i(i,1) 1 0];
i=i+1;
end
The error is Unable to perform assignment because the indices on the left side are not compatible with the
size of the right side.

Answers (1)

I believe the issue is that you are trying to assign a 2-row array into a single row of H. Hence, the dimension mismatch error. If your intent is to assign the array to 2 rows of H, then your row index must include both rows.
% Assignment to 2 rows works
A(1:2,:)=rand(2,6)
A = 2×6
0.8925 0.9049 0.9095 0.9129 0.5104 0.9256 0.1996 0.1794 0.4227 0.2812 0.9497 0.2225
% Assignment to 1 row doesn't work
A(3,:)=rand(2,6)
Unable to perform assignment because the size of the left side is 1-by-6 and the size of the right side is 2-by-6.

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R2021a

Asked:

on 2 Jul 2021

Answered:

on 3 Jul 2021

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