I want to compare two arrays and check that which value is missing in second array as compared to first one?

A=[ 0 1 1 ;
    1 1 0 ];

target=[1 2 3 4];
[m,n]=size(A);
c1=0;cover1=[];sum_coord=[];sss=0;
for i=1:m    
    cc=0;t_coordinate=[];
    for j=1:n          
            if A(i,j)==1            
                cc=cc+1;
                t_coordinate(cc,:)=j;
                sss=sss+1;
                sum_coord(sss,:)=t_coordinate(cc,:);
            end     
    end    
    display(t_coordinate)
end
sum_coord=sort(sum_coord);
sum_coord=unique(sum_coord);
display(sum_coord)

first array is "Target" and second is "sum_coord"....

Answer 1

[Rik]

You should avoid variable names like sum, as that will prevent you from using the sum function.

Your question sounds like you need the ismember function. However, it is unclear how your code relates to the question in the title.

[Aqeel Awan]

I've changed the variable name and now how it could be done?

[Rik]

Did you try to google the documentation for the ismember function?

A=[ 0 1 1 ;
    1 1 0 ];

target=[1 2 3 4];
[m,n]=size(A);
c1=0;cover1=[];sum_coord=[];sss=0;
for i=1:m    
    cc=0;t_coordinate=[];
    for j=1:n          
        if A(i,j)==1            
            cc=cc+1;
            t_coordinate(cc,:)=j;
            sss=sss+1;
            sum_coord(sss,:)=t_coordinate(cc,:);
        end     
    end    
end
sum_coord=sort(sum_coord);
sum_coord=unique(sum_coord);
disp(sum_coord)

     1
     2
     3

L=ismember(target,sum_coord);
ismissing=target( ~L );
disp(ismissing)

     4

[Aqeel Awan]

good ... thank you