How to plot the growth of interest in matlab (time on x-axis and current balance on y-axis)?

Interest is compounded continuously; P = pe^(rt) represents the growth of your savings.

P= current balance

p= initial balance

e= (number 'e') approx. 2.72

r= growth rate (expressed as decimal fraction)

t= time invested (years)

Determine the amount in your account at the end of each year if you invest $1000 at 8% (0.08) for 30 years. Plot time on the x-axis and the current balance on the y-axis.

Answer 1

[Laurent]

I'll give you one hint, because it seems to me that this is homework.

t=[0:1:30];

[Sean de Wolski]

and

exp(1)

is e

[Catherine]

It is homework. But considering I don't even know the basics, hints don't exactly help. Thanks for the uppity attitude though.