Combining two surface plots

I'm trying to combine two surface plots in a single figure. The problem is that one of the two is plotted on the wrong axis. The reason is that:
surface1 = surf(x,y,z)
surface2 = surf(x,z,y)
This is due to the mathematical equations behind x,z and y. I can't change them, i.e. rearrange z in terms of y for surface2.
Is there a way to map the two to the correct axes?

2 Comments

An example image will help to understand the problem.
Sure, here's a screenshot:
The green one is rotated wrongly; this is because the z variable is p in this case, whilst for the yellow it is a. When
i.e.
yellow = surf(x,p,a), green = surf(x,a,p)
It seems to me that I can't change the order in surf because that means rearranging the underlying equations, which I can't do in this case. When I combine the two in a single figure, a and p are inverted. It's difficult to see graphically but I'm sure that that's the problem ... just don't know how to fix it :( This instead is what the correct blue surface should be:

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 Accepted Answer

You can
ax = gca;
yellow = surf(ax, x, p, a);
hold(ax, 'on')
M = [1 0 0 1; 0 0 1 0; 0 1 0 0; 0 0 0 0];
hg = hgtransform(ax, 'Matrix', M);
green = surf(hg, x, a, p);
hold(ax, 'off')
xlim(ax, 'auto'); ylim(ax, 'auto'); zlim(ax, 'auto');

5 Comments

I get the following error:
Error using hgtransform
Invalid value for Matrix property.
ax = gca;
yellow = surf(ax, x, p, a);
hold(ax, 'on')
M = [1 0 0 0; 0 0 1 0; 0 -1 0 0; 0 0 0 1];
hg = hgtransform(ax, 'Matrix', M);
green = surf(hg, x, a, p);
hold(ax, 'off')
xlim(ax, 'auto'); ylim(ax, 'auto'); zlim(ax, 'auto');
hgtransform is insisting that one of the axes be negative; I am not sure why that is.
M = [1 0 0 0; 0 0 -1 0; 0 1 0 0; 0 0 0 1];
is another matrix that is accepted.
It now tells me the following for the 2nd surf call (green)
Data dimensions must agree.
Is it because, after hg, I've recreated a?
a = meshgrid(linspace(0,1,10));
In order for green = surf(hg, x, a, p); to work, then:
  • if x is a vector, then length(x) == size(p,2) -- columns not rows
  • if x is an array, then size(x) == size(p)
  • if a is a vector, then length(a) == size(p,1) -- rows not columns
  • if a is an array, then size(a) == size(p)
It is not an error to use an array for x by a vector for a, or a vector for x but an array for a, or a vector for both or an array for both -- but they have to match the appropriate dimension of p.

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