The goal is to create a function that will return a single "NaN" without using the nan function. I am interested to see how many different ways this can be done, so be creative and submit more than one solution if you have lots of ideas!
Nice test suite
I really really want to know that how many methods to gain NaN up to now.
Find the sum of the elements in the "second" diagonal
Convert from Base 10 to base 5
Generate a string like abbcccddddeeeee
Big numbers, least significant digits
Big numbers, repeated least significant digits
Given the name from the legend, return the handle
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