Consider the recursion relation:
x_n = (x_(n-1)*x_(n-2))^k
Given x_1, x_2, and k, x_n can be found by this definition. Write a function which takes as input arguments x_1, x_2, n and k. The output should be x_n.
For example, if x_1=exp(1), x_2=pi, n=5, and k=5/9 then:
R = get_recurse(exp(1),pi,5,4/9)
R =
2.31187497992966
Solution Stats
Problem Comments
4 Comments
Solution Comments
Show comments
Loading...
Problem Recent Solvers85
Suggested Problems
-
Remove any row in which a NaN appears
8774 Solvers
-
Check to see if a Sudoku Puzzle is Solved
338 Solvers
-
289 Solvers
-
Number of 1s in the Binary Representation of a Number
481 Solvers
-
1184 Solvers
More from this Author6
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
is there a story as to why this is "infernal"?
I hate recursion, so it is all infernal to me! Iteration is the way to go...
Test suite could helpfully include n=1 and n=2 tests. I thought that it needed extra complexity to handle these, but @bmtran's top solution shows it doesn't.
I spend a lot of time to get the correct R from the example. The issue is that you say k = 5/9 instead of 4/9 . Just a typo to correct . Thanks