Given a vector of positive integers a (>=0); How does one create the matrix where the ith column contains the vector 1:a(i) possibly padded
in->a = [3 2 4];
out->b = [1 1 1;2 2 2;3 0 3;0 0 4];
yes of course. Leading solution:
function b = matInc(a)
[b aa] = ndgrid(1:max(a), a);
b(b > aa) = 0;
Swap the input arguments
We love vectorized solutions. Problem 1 : remove the row average.
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