Problem 45502. Basic Operation with the middle number of odd matrix

Created by Muhammad Usman

Solve Later

{"relationships":[{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/document","targetMode":"","relationshipId":"rId1","target":"/matlab/document.xml"},{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/output","targetMode":"","relationshipId":"rId2","target":"/matlab/output.xml"}],"parts":[{"partUri":"/matlab/document.xml","relationship":[],"contentType":"application/vnd.mathworks.matlab.code.document+xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n<w:document xmlns:w=\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\"><w:body><w:p><w:pPr><w:pStyle w:val=\"ListParagraph\"/><w:numPr><w:numId w:val=\"2\"/></w:numPr></w:pPr><w:r><w:t>Take an odd matrix</w:t></w:r><w:r><w:t> </w:t></w:r><w:r><w:rPr><w:b/></w:rPr><w:t>like</w:t></w:r><w:r><w:t> 3-by-3</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"ListParagraph\"/><w:numPr><w:numId w:val=\"2\"/></w:numPr></w:pPr><w:r><w:t>Access the</w:t></w:r><w:r><w:t> </w:t></w:r><w:r><w:rPr><w:b/></w:rPr><w:t>middle element</w:t></w:r><w:r><w:t> of the matrix i.e in case of 3-by-3 matrix the index of the particular element is second row, second column.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"ListParagraph\"/><w:numPr><w:numId w:val=\"2\"/></w:numPr></w:pPr><w:r><w:t>Now,</w:t></w:r><w:r><w:t> </w:t></w:r><w:r><w:rPr><w:b/></w:rPr><w:t>sum</w:t></w:r><w:r><w:t> the elements in its column to it and then</w:t></w:r><w:r><w:t> </w:t></w:r><w:r><w:rPr><w:b/></w:rPr><w:t>subtract</w:t></w:r><w:r><w:t> the elements in its row to it.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"ListParagraph\"/><w:numPr><w:numId w:val=\"2\"/></w:numPr></w:pPr><w:r><w:t>What's the matrix with updated element.</w:t></w:r></w:p></w:body></w:document>"},{"partUri":"/matlab/output.xml","contentType":"text/xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"no\" ?><embeddedOutputs><metaData><evaluationState>manual</evaluationState><layoutState>code</layoutState><outputStatus>ready</outputStatus></metaData><outputArray type=\"array\"/><regionArray type=\"array\"/></embeddedOutputs>"}]}

Solve

Solution Stats

54 Solutions
25 Solvers

Last Solution submitted on Apr 12, 2023

Last 200 Solutions

Problem Comments

4 Comments

4 Comments

Show 1 older comment

William on 8 May 2020

As i understand it, the algorithm is only supposed to change the middle element of the matrix. That means the answer to problem 1 in the test suite is incorrect.

Muhammad Usman on 8 May 2020

@William, the problem is not only to change the middle term but to do basic operations with it.
In the first suite 5 is the middle number, add 2 and 8 (column elements) and then subtract 4 and 10 (row elements), so 5+2+8-4-10 = 1

William on 9 May 2020

Hi Muhammad,
Yes, I understand how the value x(2,2) was calculated, but why did the values of x(1,2) and x(3,2) change?

Binbin Qi on 9 May 2020

I do not understand why all the element in the second column equal 1 in the first test suit?

Solution Comments

Show comments

Problem Recent Solvers25

Problem Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Problem 45502. Basic Operation with the middle number of odd matrix

Solution Stats

Last 200 Solutions

Problem Comments

Solution Comments

Problem Recent Solvers25

Suggested Problems

More from this Author1

Problem Tags

Community Treasure Hunt

Problem 45502. Basic Operation with the middle number of odd matrix

Solution Stats

Last 200 Solutions

Problem Comments

Solution Comments

Problem Recent Solvers25

Suggested Problems

More from this Author1

Problem Tags

Community Treasure Hunt

Players