The aim is to remove the elements before and after NaN occurrences inside a vector.
For example:
x = [6 10 5 8 9 NaN 23 10 7 3 21 43 NaN 4 6 7 8]
The output y will be:
y = [6 10 5 8 10 7 3 21 6 7 8]
If NaNs occur at the beginning or end then first two or last two values are removed.
x=[NaN 1 2 3] yields [2 3]
NaN values will exist in every case. No case is an empty set.
Make the vector [1 2 3 4 5 6 7 8 9 10]
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