version 1.4.0.0 (3.75 KB) by
Gustavo Morales

Plots a 3D surface defined implicitly

At last Matlab do it!!!

Useful tool to plot a 3D implicit surface defined in cartesian coordinates. You can give f(x,y,z) = 0 as a string or as a function handle. Type <help ezimplot3> for usage. Remember to leave your comments and ratings...Thanks!

;)

Gustavo Morales (2021). Ezimplot3: implicit 3D functions plotter (https://www.mathworks.com/matlabcentral/fileexchange/23623-ezimplot3-implicit-3d-functions-plotter), MATLAB Central File Exchange. Retrieved .

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Jin-Yu ZhangGustavo MoralesAwanthika Senarath

Hi.

First argument "fun" must be of type character, simbolic, function handle or inline. You can't introduce a matrix.

Ezimplot3 do not graph 'data'. It graphs functions.

Awanthika SenarathHello Gustov,

Thank you for your function. I'm a newbie to matlab. I'm trying to plot my data (151 samples each with 30 readings) 151*30 matrix with 3 independent variables. I have the matrix. However, when I feed the matrix directly into your function I get the error,

Error using ezimplot3>fix_fun (line 194)

First argument "fun" must be of type character, simbolic, function handle or inline

Error in ezimplot3 (line 76)

[f_handle f_text] = fix_fun(fun); % f_handle is the anonymous f-handle for "fun"

Could you help me with this? Am I importing the data wrong?

Regards

Awanthika

pan jijunDaniel BlixtNice function. I have an spectrum problem which yields the following equation

0=sin(kx/2)*sin(ky/2)*sin(k*(1-x-y)/2)*(sin(k/2)-sin(kx/2)*sin(ky/2)*sin(k*(1-x-y)/2))

It have multiple solutions and I want to display the figure so that you can distinguish between the different levels (surfaces) of solutions.

I also have restrictions that cannot be satisfied by your function. I have x+y+z(x,y)=1. x≤y≤z.

Can you help me solve these two problem

In other words x and y takes values on the triangle limited by

x=0, 0≤y≤1/2

0≤y=x≤1/3

1/3≤y=1/2-x/2≤1/2

Thank you in advance

Matt JVery nice. I think it would be a great favor to the community, though, if you would generalize it so that when you already have a function handle, it doesn't require the Symbolic Toolbox. This is very easy to do by circumventing fix_fun as follows

if ~isempty(which('syms'))

[f_handle f_text] = fix_fun(fun); % f_handle is the anonymous f-handle for "fun"

% f_text is "fun" ready to be a title

elseif isa(fun,'function_handle')

f_handle=fun; f_text='';

else

error 'Cannot process input function'

end

Other minor remarks:

1. The syntax ezimplot3(fun,domain, color) does not parse correctly

2. You have a missing % in your help text, making about half of it disappear when doing help/doc ezimplot3

Andrey ZhigachevNice function! Thank you, I was looking for such as one for a long time.

GkcnDear Gustavo,thank you for your useful function.I tried to use it for plotting my own equation but it gives many surfaces together although i need only one surface around first root of my equation.Please can you help me how can i find it?

my equation is:

tan(sqrt(y)*(1-1/x)*z)-sqrt(y)*(x-z^2)/(x+y)*z=0

1<=x<=10 , 0.1<=y<=10 , 0<=z<=1

Thank you in advance.

ShahabNice Job Gustavo

I just needed an implicit plot in the middle of my code somewhere to show an obstacle...

You saved me a few days of work.

Thx man

Daniel LopesNice code! Well done!

You should try to combine it with the implicitplot3d(.)[go this website http://www-users.math.umd.edu/~jmr/241/surfaces.html].

It realy gives an excelent visual result as an alternative to the cranky mesh from isosurface(.) :S.

%% ____________________________________

figure,

syms x y z;

h=x^2+y^2+z^2;

implicitplot3d(h, 1, -3, 3, -3, 3, -3, 3, 40); axis equal

hold on

ezimplot3(h-1,[-5 5])

Gustavo MoralesSorry for not being a good software documenter. I'm just a Electrical Engineer .... all the "symbol part" of the code, you can replace it...

JonathanThis seems like a good function. However, I could not discover it since my time has been fruitlessly spent. This function requires the symbolic toolbox, yet no mention of this was explicitly included on this page or in the function help.

Michelle GledhillHello Gustavo,

Is there a way to add a contour plot on the x-y-plane in a similar way that the function "surfc" does?

Thank you for your time!

Gustavo MoralesHi Camilla!!! I've already aswered your email...!

Camilla ColomboHi Gustavo,

I sent you an email to gmorales@uc.edu.ve

Please let me know if you received it.

Thanks

Camilla

Gustavo MoralesHi Camilla!

Your funcion has others arguments than x,y,z?

Can you send me the code of your function?... Send it by email...

Camilla ColomboDear Gustavo,

thank you for your function. I am trying to plot an implicit function coded into an m. file. However i get an error and i think this is due to the fact that my function contains some "if condition". So I get the error at line 168 of ezimplot3:

f_sym = eval([fun,'(x,y,z)']); % evaluating FUN at the sym point (x,y,z)

do you know a way to avoid this problem?

thank you in advance

Camilla

Gustavo MoralesHi Hisham.. ok! send me the code of M1 by email...

Hisham Moideenhi Gustavo,

I tried plotting the way you suggested.

h1=ezimplot3(M1,[0.02 5 0 4 0 0.35]);

where M1 is the determinant of a matrix involving the three variables alpha,gamma,R.

I got the following error:

"??? Error using ==> ezimplot3 at 82

FUN must have no more than 3 arguments"

To make sure i dont have more than 3 unknowns, i substituted specific values for each and got a single value for my Function M1.

Is is possible that i could send you my code of generating M1 and maybe you could help me.

Problem is my function M1 is not a simple function. Its a determinant of a matrix of order 8. Some of the terms in my matrix is polynomial fit of alpha and R. So the determinant is one crazy looking expression. Matlab cant output my entire determinant value (out of line limit error).

Appreciate any help in this regard!!!

Gustavo MoralesHi...

*fun can be a string, an anonymous function handle, a .M-file handle, an inline function or a symbolic function. Any other variable present at the function (aside from alpha, gamma and R), must have a known value, that is, your function must depend only of alpha, gamma and R.

*>> domain = [min-alpha max-alpha min-gamma max-gamma min-R max-R];

ezimplot3(fun,domain);

test with the examples of help: >> help ezimplot3

regards from Venezuela!

Hisham Moideenhi Gustavo,

I have an implicit function, but the variables are alpha, gamma and R.

Can i use ezimplot3() to output my function?

Also is it possible to input different range for my variables like

ezimplot3(M1,[0.2 6 0 5 0 0.34]), will that work?

Appreciate the help and code.

Gustavo MoralesHi!

> h = ezimplot3() outputs a handle for the patch object. So you can do the folowing:

> set(h,'FaceColor','none','EdgeColor','k')

I hope I have been able to help you.

"I prefer being useful than being important"

Brian BakHi Gustavo Morales

Just as you wrote the boundaries was not large enough for the surfaces to be plottet.

Do you have any suggestions to how you kan change the surface to be a grid instead of a color?

Thanks in advance.

Very nice program btw!

Gustavo MoralesI didn't understand you... so... have you already discovered the mistake? I was trying to do something about it, and that's what I've found:

> f = '(x/(4 - 3*y))^2 + (z/(4 - 3 *y))^2 -1';

> ezimplot3(f,[-3000 3000 -10000 10000 -3000 3000]);

It produces a nice graph... maybe the function that you provided is too small...

Regards!

Gustavo Moralesthe numeric answer you get is a handle for the patch object

Brian BakMy mistake it was just the boundaries that where wrong.

Brian BakHi

Does anyone no why I can't plot the following:

f = '(x/(400^2 - 0.3*y))^2 + (z/(400^2 - 0.3 *y))^2 -1';

ezimplot3(f,[-3000 3000 -10000 10000 -3000 3000])

It just shows an empty plot from 0 to 1 on all axes. And gives the output: ans = 0.0037

thanks in advance

Gustavo MoralesDave, as you should know, you only can see plots for explicit R2 to R functions, so the index "i" must be at most 2. Your function is also known as "Parabola", and has this other explicit (not implicit) form:

f(x,y) = x^2 + y^2 ... a paraboloid

I suggest that use instead the following command:

>> plotobjective(@dejong1fcn,[-5.12 5.12;-5.12 5.12]);

;-)

Dave YapDear Gustavo, really nice and neat program.

I would like to plot a DeJong1 test function as below,

f1(x)=sum(x(i)^2), i=1:n, -5.12<=x(i)<=5.12

I'm unable to plot the Dejong1 test function.

Could you pls help me on this?

my email is dyfw@hotmail.com. Thanks in advance.

Gustavo MoralesI'd like to study ezgraph3 throughly to make -ezimplot3- a "real command", and maybe some day, Mathworks could take it ;)

And...There's a way.... try writing:

>>help ezimplot3

for usage

Tamara KoldaThis is fantastic! Just what I was looking for and what ezplot3 should do!

One questions/suggestion: Is there a way to also choose the color of the surface that's plotted? I was able to do it manually using the get/set commands, but I was hoping to be able to do it using the function directly.

Thanks for sharing this with the community.