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I am trying to do a double integral of a function using the simpsons 1/3 rule, need help with setup
function I =simsonss(func,a,b,n) x=a; h=(b-a)/n; s=func(a); for i=1:2:n-1 x=a+i*h; s=s+(4* func(x)); ...
I am trying to do a double integral of a function using the simpsons 1/3 rule, need help with setup
function I =simsonss(func,a,b,n) x=a; h=(b-a)/n; s=func(a); for i=1:2:n-1 x=a+i*h; s=s+(4* func(x)); ...
8 years ago | 0

