Statistics
RANK
28,473
of 301,433
REPUTATION
1
CONTRIBUTIONS
6 Questions
0 Answers
ANSWER ACCEPTANCE
50.0%
VOTES RECEIVED
1
RANK
of 21,272
REPUTATION
N/A
AVERAGE RATING
0.00
CONTRIBUTIONS
0 Files
DOWNLOADS
0
ALL TIME DOWNLOADS
0
CONTRIBUTIONS
0 Posts
CONTRIBUTIONS
0 Public Channels
AVERAGE RATING
CONTRIBUTIONS
0 Discussions
AVERAGE NO. OF LIKES
Feeds
Question
How to find the X-coordinate of the plot knowing the Y-value?
I am carrying out the Fast Fourier Transform for a time series of data. I have found out the maximum value of the voltage amplit...
7 years ago | 1 answer | 0
1
answerQuestion
While trying to solve two simultaneous ODE's in MuPad, how to solve using boundary conditions for two different variables?
s:=({[y''''(x) = R1[{x + 3 - 2*y(x)}*y''(x) - 2*(R2/R1)*z(x)*z'(x)], z''(x) = R1[{2*z(x) + x*z'(x) + 2*z(x)*y'(x) + 2*z'(x)*y(...
7 years ago | 0 answers | 0
0
answersQuestion
I require a solution for the set od ODE's using MATLAB function 'bvp4c'
The code that I've written is as follows: function bvp_code_matlab_3 options = bvpset('stats','off', 'RelTol', 1e-6); so...
7 years ago | 1 answer | 0
1
answerQuestion
I need help solving this fourth order ODE using bvp4c. I don't have much experience with bvp4c and I am unable to solve this one question that involves plotting graphs for three different parameters for a fourth order simultaneous ODE.
Two differential equations are as follows: f'''' = R1 [ 3* f'' + ( n - 2* f) * f'' - 2...
7 years ago | 0 answers | 0
0
answersQuestion
I have been working with bvp4c for a while now and I am unable to solve this one question that involves plotting graphs for three different parameters for a fourth order simultaneous ODE.
Two differential equations are as follows: f'''' = R1 [ 3* f'' + ( n - 2* f) * f'' - 2*( R2/R1) * g* g' ] g'' = R1 [ 2*g + n*...
7 years ago | 0 answers | 0
0
answersQuestion
I'm trying to solve a fourth order ordinary differential equation using the bvp4c function. However, I am getting a few errors in my code.
H'''' - 5(H*H''' + 4GG') = 0 ; G'' + 5(H'*G - H*G') = 0 With the boundary conditions: G(0) = 0.5, H(0) = 0, H'(0) = 0,G(1) = ...
7 years ago | 1 answer | 1
1
answerSolved
Times 2 - START HERE
Try out this test problem first. Given the variable x as your input, multiply it by two and put the result in y. Examples:...
8 years ago


