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Question
The approximation of the ln(1.9) using the Taylor series ln(1-x) = -sum of x^k/k, -1 less than or equal to x less than 1, I can't figure out how to code this properly
x=-0.9; target_equation = log(1-x); series_sum = 0; difference = abs(target_equation - series_sum); threshold = 1*10^-10; c...
2 years ago | 1 answer | 0
