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Neda


Active since 2012

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why real part of fft (exp(at)) is negative in some parts in contrary to analytical calculation of fft(exp(at))?
Thanks for the reply. I agree with you that symmetry is important. But my problem is about the real values calculated from FFT. ...

12 years ago | 0

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why real part of fft (exp(at)) is negative in some parts in contrary to analytical calculation of fft(exp(at))?
Hi, I want to calculate the *real part* of fourier transform of A = exp(at) where "a" is a constant and t = [0 T]. when I calc...

12 years ago | 2 answers | 0

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