Nested for loop still not working...

Why will this work...

if true
  % code
end  
InstNames = fieldnames(HistData);
HistData.(InstNames{1}).(DataNames{1}) = SepHistData(:,1,1);
HistData.(InstNames{1}).(DataNames{2}) = SepHistData(:,2,1);
HistData.(InstNames{1}).(DataNames{3}) = SepHistData(:,3,1);
HistData.(InstNames{1}).(DataNames{4}) = SepHistData(:,4,1);
HistData.(InstNames{1}).(DataNames{5}) = SepHistData(:,5,1);
HistData.(InstNames{1}).(DataNames{6}) = SepHistData(:,6,1);
HistData.(InstNames{1}).(DataNames{7}) = SepHistData(:,7,1);
HistData.(InstNames{2}).(DataNames{1}) = SepHistData(:,1,2);
HistData.(InstNames{2}).(DataNames{2}) = SepHistData(:,2,2);
HistData.(InstNames{2}).(DataNames{3}) = SepHistData(:,3,2);
HistData.(InstNames{2}).(DataNames{4}) = SepHistData(:,4,2);
HistData.(InstNames{2}).(DataNames{5}) = SepHistData(:,5,2);
HistData.(InstNames{2}).(DataNames{6}) = SepHistData(:,6,2);
HistData.(InstNames{2}).(DataNames{7}) = SepHistData(:,7,2);

and this won't...

if true
  % code
end
for k = length(InstNames)
  for i = length(DataNames)
  HistData.(InstNames{k}).(DataNames{i}) = SepHistData(:,i,k);
  end
end

Answer 1

[Paul]

You should do

for k = 1:length(InstNames)
  for i = 1:length(DataNames)

So add the 1:. This:

for k = length(InstNames)

assigns the value length(InstNames) to k without looping.

[Justin]

Thanks so much. These are the moments when one is reminded he's a beginner (I feel like exclaiming, DUH!).

Thanks, again.

Answer 2

[Sean de Wolski]

length(DataNames)

Will return something like seven I imagine.

Your for-loops will eventually want

SepHistData(7,7)

Which doesn't exist. This is not one of the options above

It seems to me like you want:

for k = 1:2
  for i = 1:length(DataNames)
     etc.

[Justin]

Sorry, that was a bad example, this is what I am really working with.

if true
  % code
end
for k = length(InstNames)
  for i = length(DataNames)
  HistData.(InstNames{k}).(DataNames{i}) = SepHistData(:,i,k);
  end
end   
clearvars i k