Array problem
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Hey every1, I am actually having trouble with arrays!! I have my plot and is underneath and it is not saved in array at the moment but I would like to story it in array so I should have a value for[x1,y1] in an array.. the question is how can I get the values of the plots and store it in an array???
x = linspace(min(Sa),max(Sa),100);
y = pchip(Sa,lambda(Sa),X);
plot(x,y)
a [x,y] then is it by looping through it and if it is how can we say then the next value in x and y.. I want to store each pair value(x,y) of the plot in an array???
Your help will be appreciated!
Accepted Answer
More Answers (2)
Walter Roberson
on 26 Jul 2011
h = find(gca,'type','line');
xd = get(h, 'XData');
yd = get(h, 'YData');
7 Comments
Susan
on 26 Jul 2011
Oleg Komarov
on 26 Jul 2011
findobj(gca,'type','line')
Susan
on 26 Jul 2011
Susan
on 26 Jul 2011
Nathan Greco
on 26 Jul 2011
After you create your plot, type the lines Walter provided you.
findobj(gca,'type','line') will return the handle of the line object on your current plot. With this handle, you can retrieve the x and y data by using get(h,'XData') and get(h,'YData') respectively...
Susan
on 26 Jul 2011
Nathan Greco
on 26 Jul 2011
And he corrected his "find..." line to be "findobj..." within the comments.
Susan
on 26 Jul 2011
0 votes
4 Comments
Nathan Greco
on 26 Jul 2011
Please be more precise. Are the values on the plot that you are trying to retrieve the same ones that you used to create the plot? Are you trying to take smaller stepped values from the plot? Saying (x1,y1) etc. is not very helpful.
Susan
on 26 Jul 2011
Nathan Greco
on 26 Jul 2011
Are they not already stored in arrays? If I'm not mistaken, that is exactly what your original x and y arrays are. If you wanted them in one array, just concatenate them together as Paulo answered. If you wanted to retrieve that same data from the plot (why? I don't know), follow Walter's method, replacing his "h = find(gca,'type','line');" with "h = findobj(gca,'type','line');". If this doesn't work for you, please say why not.
Susan
on 26 Jul 2011
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