second order ODE fun. with polynomial and loop
Show older comments
x''=(W/M)+((c*x')/M)+((K*(x*cosd((Thet1))-(Cr+(Hd*(sind((180)/((ph)*(Thet1))))))).^3/2 *(cos(Thet1)))/M)
this is the equation to solve
Di=0.0321;
Do=54.67*10^-3;
D=43.385*10^-3;
d=11.274*10^-3;
z=7;
Cr=11.285*10^-6;
M=3;
c=200;
Om=125.66;
Oc=46.5;
h=37*10^-6;
x0=10^-9;
x'0=10^-9;
ph=0.4623;
W=100;
K=8.37536*10^9;
Pi=3.14;
x(1)=x0; v(1)=v0;
j=1; tt=1;
Hd=0.1*10^-3;
for t=0:h:0.7
for i=1:7;
Thet=((46.5)*t)+(((7-i)*(2*3.14)/7)) ;
Thet2=(Thet*180)/3.14;
if (Thet2<=360)
Thet1=Thet2;
elseif (360<=Thet2)&&(Thet2<=720)
Thet1=Thet2-360;
elseif (720<=Thet2)&&(Thet2<=1080)
Thet1=Thet2-720;
elseif (1080<=Thet2)&&(Thet2<=1440)
Thet1=Thet2-1080;
elseif (1440<=Thet2)&&(Thet2<=1800)
Thet1=Thet2-1440;
elseif (1800<=Thet2)&&(Thet2<=2160)
Thet1=Thet2-1800;
elseif (2160<=Thet2)&&(Thet2<=2520)
Thet1=Thet2-2160;
elseif (2520<=Thet2)&&(Thet2<=2880)
Thet1=Thet2-2520;
else
Thet1=Thet2-2880;
end
if (0<=Thet1)&&(Thet1<=0.4623)
%Fx(j)=K*(x*cosd((Thet1))-(Cr+(Hd*(sind((180)/((ph)*(Thet1))))))).^3/2 *(cos(Thet1));
y0=[10^-9;10^-9];
[t,y]=ode45('line',[t t+h],y0);
else
% Fx(j)=0; cosd(Thet1);
end
j=j+1;
end
function fx=line(t,y)
Cr=11.285*10^-6;
c=200;
ph=0.4623;
W=100;
K=8.37536*10^9;
Hd=0.1*10^-3;
fx=zeros(2,1);
fx(1)=y(2);
fx(2)=((33.34)+(66.67*y(2))+((2.791*10^9*(y(1)*cosd((Thet1))-(Cr+(Hd*(sind((180)/((ph)*(Thet1))))))).^3/2 *(cos(Thet1))))); pls tell me how to solve this equation
2 Comments
Note,
if 5<thet<10
will not function in MATLAB code as expected. It should be
if 5<thet & thet<10
Star Strider
on 5 May 2014
Please post the code for your entire ODE function, from the function line the the last end statement.
Answers (0)
Categories
Find more on Ordinary Differential Equations in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!