MATLAB Answers

Error unexpected matlab operator

6 views (last 30 days)
Aws on 18 Jun 2014
Edited: Aws on 18 Jun 2014
Hi, every body
i try to execute the code given in the help of matlab, but there is something wrong, this is the code:
if true %code f:=plot::Function2d(sin(x),x=0..2*PI)
f:=plot::Function2d(sin(x),x=0..2*PI) | Error: The expression to the left of the equals sign is not a valid target for an assignment. end
so i clik on the space bar after "f" the code will be like this:
if true %code f :=plot::Function2d(sin(x),x=0..2*PI)
Undefined function 'f' for input arguments of type 'char'. end
i delete "f", the code will be like:
if true %code plot::Function2d(sin(x),x=0..2*PI)
plot::Function2d(sin(x),x=0..2*PI) | Error: Unexpected MATLAB operator.
same result for the belowing codes
if true %code plot(plot::Function2d(sin(x),x=0..2*PI)) end
if true %cdoe plot(plot::Function2d(sin(x),x=0..2*PI)): end
and if true %code plot(plot::Function2d(sin(x),x=0..2*PI)); end
so if the codes in the help deosn't work, how can i learn matlab?
my matlab version is complete, 64 bits, 2013b on windows 7.
Aws on 18 Jun 2014
i think it deosn't work exactly the "code"

Sign in to comment.

Answers (1)

Azzi Abdelmalek
Azzi Abdelmalek on 18 Jun 2014
This looks like Mupad code, You have to look at Mupad help
doc mupad
If you are new with matlab, then begin with Matlab getting started
  1 Comment
Aws on 18 Jun 2014
thank you Abdelmalek, that's true it's a mupad code. Salem alaykom. Have a nice day.

Sign in to comment.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!