Saving matrix after each for loop, note size of n(k) is not constant

Dear all, I have to save the vector after each loop, here size of n(k) varies. I am not able to save the values of Z after each loop

alpha=(17*pi)/180;        %slope angle
dz=2;         %depth of water table from the suface
dlz=4;        % toltal depth of slope
fi=(25*pi)/180;          %friction angle
C=4;          %4 kpa=0.4 N/cm^2
gsat=21;      %21 kN/m^3=0.021 N/cm3
gw=9.8;       %9.81 Kn/m^3=0.0098N/cm3
Dzero=0.0004;        %0.0004m^2/s=4 cm2/s
ksat=1e-5;      %e-5 m/s
iz=7.2/1000;        %iz=7.2 mm/h= 2e-4 cm/s
deltat=10:10:600;
q1=Dzero*cos(alpha)*cos(alpha);
q2=deltat*q1;
deltaz=sqrt(q2);
r=q2./deltaz.^2;
n=round(dlz./(deltaz)+1);

% deltat=60;      %time step
% deltaz=0.1482;     %space step
% T=12*60*60;     %time duration of rainfall= 12h to seconds
% r=(deltat/deltaz^2)*Dzero*cos(alpha)*cos(alpha);
% n=27;          %time step, based on T
for k=1:60;    
    Z=linspace(deltaz(k),4,n(k));% depth in cm
    mat(k,:)=Z
    % Z=Z';
% display (Z)
end

Answer 1

[Matt J]

Use a cell array instead,

    mat{k}=Z;

[advaita vedanta]

Dear Matt,

The command is not working.

Thank you for the reply

[Matt J]

Worked fine for me.

Answer 2

[Adam]

I can't quite work out from glancing at your code exactly what n is, but can you not just calculate the n(k) ahead of the loop and presize a result array (using zeros or NaNs if zero is a valid value for your results) based on the largest of the n(k) values and fill only those elements of the array required for each k?

[advaita vedanta]

Dear Adam,

Actually the value of n varies, where n is number of nodes in finite difference method. I want to calculate the value of Z vector for every n(k). Thank you.