Error: Operator '-' is not supported for operands of type 'function_handle'.
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Daniela Würmseer
on 10 Feb 2022
Commented: Star Strider
on 10 Feb 2022
Hello, i have the following Code:
f1 = [-1,-1];
f2=@(x)-10*x(1)+x(1)^2-4*x(2)+x(2)^2;
A = [3 1;
2 1 ;
1 2];
b = [12; 9; 12];
z = [0,0];
d = [-1,0];
Method(f1,f2,A,b,z,d);
function [x,alpha] = Method(f1,f2,A,b,z,d)
f =@(x)-x(size(A,2)+1);
x0 = (zeros(1,size(A,2) + 1));
lb = [(zeros(1,size(A,2))),-Inf];
if (~isempty(f1))
Anew = [f1,-d(1)];
Anew(2:size(A,1)+1,1:size(A,2)) = A;
bnew = [z(1);b];
c1 =@(x) f2 - d(2)*x(size(A,2)+1) - z(2);
(else ... %in this case Anew,bnew and c1 would look different)
end
nonlincon = @constr;
function [c,ceq] = constr(x)
c = c1;
ceq = [];
end
[x,alpha]=fmincon(f,x0,Anew,bnew,[],[],lb,[],nonlincon);
end
This gives me the following error: Operator '-' is not supported for operands of type 'function_handle'.
I know that it is because of the line "c1 =@(x) f2 - d(2)*x(size(A,2)+1) - z(2);". Does someone knows how i could solve this problem? Thanks.
2 Comments
David Hill
on 10 Feb 2022
A general description of what you are trying to do with inputs and expected outputs would be helpful. I cannot follow your code (lots of problems).
Accepted Answer
Star Strider
on 10 Feb 2022
To be used in calculations, functions must be evaluated, and that means providing them with an argument.
See if this provides the desired result:
c1 =@(x) f2(x) - d(2)*x(size(A,2)+1) - z(2);
I am confindent that will work and not throw the previous error. I have not tested the code with this correction.
.
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