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# Plotting a function over an interval

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Kevin on 27 Sep 2011
Answered: Kris Hoffman on 29 Nov 2020
Hi,
I'm dealing with defining a function and then plotting it. The function is y1= arctan(exp(x)*(x-1))+ pi/2 which I need to plot it over interval x=0:0.1:2 , but every time I get an error. What do I need to do?
I did this:
x = 0:.01:2;
y1= arctan(exp(x)*(x-1))+ pi/2
plot(x,y1)
Also, if I want to have several functions plotted in a same window but with different colors, what should I do?
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### Accepted Answer

the cyclist on 27 Sep 2011
You need to use ".*" instead of "*" to multiply each element of the vector, and also the inverse tangent function in MATLAB is atan() not arctan():
>> y1= atan(exp(x).*(x-1))+ pi/2
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### More Answers (2)

Fangjun Jiang on 27 Sep 2011
You mean this?
x = 0:.01:2;
y1= atan(exp(x).*(x-1))+ pi/2;
plot(x,y1);
help plot for details.
plot(x1,y1,'r',x2,y2,'g',x3,y3,'b')
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Kris Hoffman on 29 Nov 2020
Tought I'd add to this answer.
y1 = @(x) atan(exp(x).*(x-1))+ pi/2
fplot(y1,[0,2])
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