convert cell to an integrable function

Dear all,

I want to enter several functions as function handles as input to a function and integrate them according the the prescribed variable in handle, a schematic representation of my request is as follow:

function y=ftest(func)
for i=1:size(func,2)
    f=func;
    ff=f{i};    
    y(i)=integral(@(var) ff(var),0,1);
end
end

Any help would be greatly appreciated :)

[Jan]

Yes, this looks good. I'd omit the indirection over f and use func directly. And if func contains a cell of function handles already, there is no need to convert them to a function handle:

function y=ftest(func)
y = zeros(1, size(func, 2));  % Pre-allocate
for i = 1:size(func,2)
    ff   = func{i};    
    y(i) = integral(ff, 0, 1);  % Or directly: integral(func{i}, 0, 1);
end
end

Do you have problems with your code? What exactly do you use as input? Do you get an error message? If so, which one?

[Mohammadfarid ghasemi]

It worked, thank you so much:)

Answer 1

[Joel Van Sickel]

This question was answered by Jan in the comments. To clean up the answers section, I am posting it down here as well:

Yes, this looks good. I'd omit the indirection over f and use func directly. And if func contains a cell of function handles already, there is no need to convert them to a function handle:

ThemeCopy

function y=ftest(func)

y = zeros(1, size(func, 2)); % Pre-allocate

for i = 1:size(func,2)

ff = func{i};

y(i) = integral(ff, 0, 1); % Or directly: integral(func{i}, 0, 1);

end

end

Do you have problems with your code? What exactly do you use as input? Do you get an error message? If so, which one?