# Rounding towards zero or from zero

6 views (last 30 days)
Nick Austinos on 26 Sep 2022
Answered: Image Analyst on 26 Sep 2022
Hi all; I want to round 3.6 to 3 but funny enough all the 'tozero' and 'fromzero' tiebreakers are returning the same answer i.e 4 which i dont want. How can this issue be fixed?
x=3.6
y=round(x,"TieBreaker","tozero")
z=round(x,"TieBreaker","fromzero")

Les Beckham on 26 Sep 2022
Edited: Les Beckham on 26 Sep 2022
There is no tie involved in rounding 3.6. If you wish, you can use floor instead:
floor(3.6)
ans = 3
If x was 3.5 instead, that would be a tie:
x = 3.5;
y=round(x,"TieBreaker","tozero")
y = 3
z=round(x,"TieBreaker","fromzero")
z = 4
##### 2 CommentsShowHide 1 older comment
Les Beckham on 26 Sep 2022
You are quite welcome.

### More Answers (3)

Sam Chak on 26 Sep 2022
Does this work for you?
x = 3.6;
y = floor(x)
y = 3

Steven Lord on 26 Sep 2022
The tiebreaker methods only apply when the quantity to be rounded is halfway between the two numbers to which it could be rounded. So if you had 3.5 that's halfway between 3 and 4 and the tiebreaker would determine to which of those numbers 3.5 gets rounded.
round(3.5, 'TieBreaker', 'tozero')
ans = 3
round(3.5, 'TieBreaker', 'fromzero')
ans = 4
There's no tie to be broken if you're rounding 3.6.
There are other rounding functions that you may want to use instead of round. See their help or documentation pages for more information on each function's specific behavior.
[fix(3.6), floor(3.6), round(3.6), ceil(3.6)]
ans = 1×4
3 3 4 4

Image Analyst on 26 Sep 2022
Try fix it rounds towards zero regardless if it's positive or negative, unlike floor which rounds towards negative infinity.
v = fix(3.6)
v = 3
v = fix(-9.4)
v = -9
v = floor(-9.4)
v = -10

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