Reorder vector without for loop

I would like to do the following without using the for loop:

for delta=1:540 % get circle points from the line.
    vectorB((delta-1)*(1080)+1:(delta)*(1080),:)=vectorA(delta:540:583200,:); % both vecs of size 583200x1000
end % delta 

This loop grabs every 540th point in a vector, stores, then increments the amount by 1 and repeats,...,etc.

Is it possible to use a built in function to do the same? Also, I plan to export to C, so whatever function must be supported.

Currently, matlab is more performant than the C coder result.

Answer 1

[Chunru]

A = randn(583200, 10);
B =reshape(A, 540, [], 10);
B = permute(B, [2 1 3]);
B = reshape(B, 583200, 10);

whos

  Name             Size               Bytes  Class     Attributes

  A           583200x10            46656000  double              
  B           583200x10            46656000  double              
  cmdout           1x33                  66  char                

% To verify the results
A(1:540:end, 1)  % every 540th points

ans = 1080×1

0.3265 -0.1556 1.3238 -0.5684 -0.7725 -1.6892 1.3998 -1.0533 1.1349 2.0951

B(1:10, 1)     % 1st 10 points

ans = 10×1

0.3265 -0.1556 1.3238 -0.5684 -0.7725 -1.6892 1.3998 -1.0533 1.1349 2.0951

[Science Machine]

the resulting matrix ought to be the same dimension of the original. This does not give me what I want

[Chunru]

What you want is B. B and A has same dimension as shown above. A small number (not all) of data is shown to verify that the result is correct.

[Science Machine]

you made A = randn(583200, 1); but its A = randn(583200, 1000); In that case A and B don't have the same dimension

[Chunru]

OK. Now A & B are of the size you specified. (use a smaller value for 2nd dimension)