How to change default incremental coordinate values of xData, yData in streamline plot?

When I extract the coordinate of Streamlines it gives coordinate values with default 0.1 spacing. I want to change the values but can't find it.

load wind
xlim = 0:1:255;
ylim = -256:1:0;
[verts averts] = streamslice(u,v,w,10,10,10);
s_slice = streamline([verts averts]);
spd = sqrt(u.*u + v.*v + w.*w);
hold on; slice(spd,10,10,10);
colormap(hot)
shading interp
view(30,50); axis(volumebounds(spd));
camlight; material([.5 1 0])

xData = get(s_slice, 'XData');
yData = get(s_slice, 'YData');

Answer 1

[Gayatri Rathod]

Hi Suman,

To change the default incremental coordinate values of xData and yData in a streamline plot, you need to modify the spacing parameter when calling the streamslice function.

The streamslice function has the following syntax:

[verts, averts] = streamslice(X, Y, Z, U, V, W, startx, starty, startz) 

where X, Y, and Z specify the coordinates of the data grid, and U, V, and W specify the vector components. The startx, starty, and startz arguments specify the starting points of the streamlines.

To change the spacing of the streamlines, you can modify the startx, starty, and startz arguments. For example, you can specify the spacing to be 0.5 as follows:

spacing = 0.5; 
[x, y, z] = meshgrid(xlim, ylim, zlim); 
startx = x(1:spacing:end, 1:spacing:end, 1:spacing:end); 
starty = y(1:spacing:end, 1:spacing:end, 1:spacing:end); 
startz = z(1:spacing:end, 1:spacing:end, 1:spacing:end); 
[verts, averts] = streamslice(u, v, w, [], [], [], startx, starty, startz); 

Here, meshgrid is used to create a grid of starting coordinates with the same dimensions as u, v, and w and startx, starty, and startz are created by selecting every spacing element from the grid. This will create a grid of starting coordinates with 0.5 spacing in all three dimensions.

You can read more about the streamslice and meshgrid functions from the following documentations: streamslice Function, meshgrid Function

Hope it helps!

Regards,

Gayatri Rathod

[Suman]

Thank you so much @Gayatri Rathod.