Adding more values to an array every loop

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Im trying to add a new value to y, as the loop progresses, to create an array, in this instance y=[1,3,5,7]. Meanwhile, all I get is the final number of that array, y=7 as a result. I know that this happens because the values are not added one by one but are all added spontaneously, so the seven fits the criteria for the "if" , but I dont have a clue on how to fix this.
Any help or tip would be appreciated, I have been stuck with this for hours and I cant find any solution online...
clear
y=0;
for k=1:2:10;
x=[1:10];
if sum(y.^2)>30
break
end
y=x(k);
end
disp(y)

Accepted Answer

Matt J
Matt J on 2 Dec 2023
Edited: Matt J on 2 Dec 2023
One possibility,
y=nan(1,100);
s=0;
for k=1:numel(y)
y(k)=2*k-1;
s=s+y(k).^2;
if s>40,
y=y(1:k);
break;
end
end
y
y = 1×4
1 3 5 7
  1 Comment
Odysseas
Odysseas on 3 Dec 2023
Thanks, this will do! I will try to compare it to my attempts to find other possible solutions.

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