Not enough input arguments

Question

0 votes

Hi all, I am a little perplexed by this warning from matlab: "Not enough input arguments" for my following code. I've looked for documentation to see the problem, but it none of them proved to be helpful to my problem. This warning occured at the line "P = z.p" line 47

tic
%% Preparation 
clc; clear
data = importdata("FCPIB-293K-2.5mW-400nm-Jan072021 -ibg -bg -chirp.csv"); % insert file path within parenthesis 
load Steady_State_Parameter_Values.mat
z = load("Steady_State_Parameter_Values.mat");
%% Preamble 
% Fundamental constants
h = 4.1356677*10^-15; % units: eV/ Hz
c = 3*10^8; % SI units
kB = 8.617333268*10^-5; % units: eV/ K
% Parameters from steady state fitting
A1 = p(1,1);
A2 = p(1,2);
Eg = p(1,3);
Eb = p(1,4);
R = p(1,5);
g = p(1,6);
% Data 
Wavelength = data(:, 1);% units: nm
E = (h*c)./(Wavelength*10^-9);
delay_t = data(1, :);
carrier_T = [1198.8, 816.7, 446.8, 328.7]; 
col1 = 56;
col2 = 63;
col3 = 74;
col4 = 87;
% Data for fitting 
Range_E = E >= 1.5 & E <= 2.0;
Range_W = Wavelength >= (h*c)/(2.0*10^-9) & Wavelength <= (h*c)/(1.5*10^-9);
E_p = E(Range_E); % selected probe energies
data_new2 = data(Range_W, [col1,col2,col3,col4]);
delta_Abs1 = data(Range_W,col1);
delta_Abs2 = data(Range_W,col2);
delta_Abs3 = data(Range_W,col3);
delta_Abs4 = data(Range_W,col4);
% Fitting function: Elliott's Model for Transient Absorption
function F = EM_TA_wR1(x, e_p, z)
P = z.p;
kB = 8.617333268*10^-5; % units: eV/ K 
A1 = P(1,1);
A2 = P(1,2);
Eg = P(1,3);
Eb = P(1,4);
R = P(1,5);
g = P(1,6);
carrier_T = [1198.8, 816.7, 446.8, 328.7]; 
    for i = numel(e_p)
    E_p = e_p(i);
    F(i) = x(5)*A1.*((2.*pi.*sqrt(x(2)))./E_p).*1/g.*(integral(@(E)sech(((E_p - E)./g)).*(1 + 10.*R.*(E - x(1)) + ...
    126.*(R).^2.*(E - x(1)).^2)./(1 - exp(-2.*pi.*sqrt(x(2)./(E - x(1))))), x(1), Inf, 'ArrayValued', 1)).*(1 - 1./(1 + exp((E_p - x(4))./(kB.*carrier_T(1,1))))).^2 - ...
    A1.*(2.*pi.*sqrt(Eb)/E_p).*(1/g).*...
    (integral(@(e)sech(((E_p - e)./g)).*(1 + 10.*R.*(e - Eg) + ...
    126.*(R).^2.*(e - Eg).^2)./(1 - exp(-2.*pi.*sqrt(Eb./(e - Eg)))), Eg, Inf, 'ArrayValued', 1)) + ...
    x(6).*A2.*(4.*pi.*(x(2)).^3/2).*1/x(3).*(...
    (1/1^3).*sech((E_p - x(1) + x(2)./1^2)./x(3)) + ...
    (1/2^3).*sech((E_p - x(1) + x(2)./2^2)./x(3)) + ...
    (1/3^3).*sech((E_p - x(1) + x(2)./3^2)./x(3)) + ...
    (1/4^3).*sech((E_p - x(1) + x(2)./4^2)./x(3)) + ...
    (1/5^3).*sech((E_p - x(1) + x(2)./5^2)./x(3)) + ...
    (1/6^3).*sech((E_p - x(1) + x(2)./6^2)./x(3)) + ...
    (1/7^3).*sech((E_p - x(1) + x(2)./7^2)./x(3))) - ...
    A2.*(4.*pi.*Eb.^3/2).*1/g.*(...
    (1./1.^3).*sech((E_p - Eg + Eb./1.^2)./g) + ...
    (1./2.^3).*sech((E_p - Eg + Eb./2.^2)./g) + ...
    (1./3.^3).*sech((E_p - Eg + Eb./3.^2)./g) + ...
    (1./4.^3).*sech((E_p - Eg + Eb./4.^2)./g) + ...
    (1./5.^3).*sech((E_p - Eg + Eb./5.^2)./g) + ...
    (1./6.^3).*sech((E_p - Eg + Eb./6.^2)./g) + ...
    (1./7.^3).*sech((E_p - Eg + Eb./7.^2)./g)); 
    end
F = F(:);
end 
% Solver
lb = [Eg, Eb, g, 0.3, 0.5, 0.2]; ub = [55, 0.05, 0.05, 20, 2, 1];
x0 = [1.65, 0.03, 0.03, 1.3, 1, 0.3]; 
optim_lsq = optimoptions('lsqcurvefit', 'Algorithm', 'levenberg-marquardt', 'MaxFunctionEvaluations',10^5, 'MaxIterations', 10^5, 'FunctionTolerance',10^-10, 'StepTolerance', 10^-10);
delta_Abs(:, 1) = data_new2(:, 1);
carrierT = carrier_T(1, 1);
x(1, :) = lsqcurvefit(@(x, e_p) EM_TA_wR1, x0, E_p, delta_Abs(:, 1), lb, ub, optim_lsq);
Not enough input arguments.

Error in solution>EM_TA_wR1 (line 47)
P = z.p;

Error in solution>@(x,e_p)EM_TA_wR1 (line 89)
x(1, :) = lsqcurvefit(@(x, e_p) EM_TA_wR1, x0, E_p, delta_Abs(:, 1), lb, ub, optim_lsq);

Error in lsqcurvefit (line 272)
            initVals.F = feval(funfcn_x_xdata{3},xCurrent,XDATA,varargin{:});

Caused by:
    Failure in initial objective function evaluation. LSQCURVEFIT cannot continue.
plot(E_p, delta_Abs(:, 1), 'o')
hold on
plot(E_p, EM_TA_wR1(x(1, :), E_p, Z), 'LineWidth', 4.0)
hold off
for n = 2:4
delta_Abs(:, n) = data_new2(:,n);
carrierT = carrier_T(1, n);
[x(n, :), residualnorm, residual, exitflag, output, lambda, jacobian] = lsqcurvefit(@(x, E_p) EM_TA_wR(x, E_p, Z), x(n-1, :), E_p, delta_Abs(:, n), lb, ub, optim_lsq);
plot(E_p, delta_Abs(:, n), 'o')
hold on
plot(E_p, EM_TA_wRn(x(n, :), E_p, Z), 'LineWidth', 4.0)
xlabel('Probe Photon Energy (eV)')
ylabel('\Delta A (O.D.)')
legend('0.5 ps', '1.0 ps', '2.0 ps', '4.0 ps', 'Location', 'southeast')
end 

0 Comments
Show -2 older comments Hide -2 older comments

Sign in to comment.

Sign in to answer this question.

Follow Question

Answer 1

Stephen23 on 11 Jul 2024

Open in MATLAB Online

0 votes

"I am a little perplexed by this warning from matlab: "Not enough input arguments" for my following code"

Lets take a look at how you call the function here:

x(1, :) = lsqcurvefit(@(x, e_p) EM_TA_wR1, x0, E_p, delta_Abs(:, 1), lb, ub, optim_lsq);
%                                        ^ zero inputs here

Although you wrote the function EM_TA_wR1 to require three inputs, when you defined that anonymous function you call it with zero inputs. That clearly will not work, you need to call it with all of its required inputs, probably something like this:

@(x, e_p) EM_TA_wR1(x,e_p,z)

2 Comments
Show None Hide None

Stephen23 on 11 Jul 2024

Edited: Stephen23 on 11 Jul 2024

Open in MATLAB Online

Lets try it with your uploaded data.

Note that I also:

replaced the very unfortunate IMPORTDATA with the much more reliable, recommended READMATRIX
removed duplicate LOAD calls
marked unused variables

Now the anonymous function is correctly defined it does not throw an error when it is called. However you have problems due to the fact that your initial conditions lead to lots of NaNs in the objective function output. You will have to debug those.

data = readmatrix("FCPIB-293K-2.5mW-400nm-Jan072021 -ibg -bg -chirp.csv");
z = load("Steady_State_Parameter_Values.mat");
%% Preamble
% Fundamental constants
h = 4.1356677*10^-15; % units: eV/ Hz
c = 3*10^8; % SI units
kB = 8.617333268*10^-5; % units: eV/ K             !!!! this is unused !!!!
% Parameters from steady state fitting
A1 = z.p(1,1); %                                   !!!! this is unused !!!!
A2 = z.p(1,2); %                                   !!!! this is unused !!!!
Eg = z.p(1,3);
Eb = z.p(1,4);
R = z.p(1,5); %                                    !!!! this is unused !!!!
g = z.p(1,6); %                                    !!!! this is unused !!!!
% Data
Wavelength = data(:, 1);% units: nm
E = (h*c)./(Wavelength*10^-9);
delay_t = data(1, :); %                            !!!! this is unused !!!!
carrier_T = [1198.8, 816.7, 446.8, 328.7];
col1 = 56;
col2 = 63;
col3 = 74;
col4 = 87;
% Data for fitting
Range_E = E >= 1.5 & E <= 2.0;
Range_W = Wavelength >= (h*c)/(2.0*10^-9) & Wavelength <= (h*c)/(1.5*10^-9);
E_p = E(Range_E); % selected probe energies
data_new2 = data(Range_W, [col1,col2,col3,col4]);
delta_Abs1 = data(Range_W,col1); %                 !!!! this is unused !!!!
delta_Abs2 = data(Range_W,col2); %                 !!!! this is unused !!!!
delta_Abs3 = data(Range_W,col3); %                 !!!! this is unused !!!!
delta_Abs4 = data(Range_W,col4); %                 !!!! this is unused !!!!
% Solver
lb = [Eg, Eb, g, 0.3, 0.5, 0.2];
ub = [55, 0.05, 0.05, 20, 2, 1];
x0 = [1.65, 0.03, 0.03, 1.3, 1, 0.3];
optim_lsq = optimoptions('lsqcurvefit', 'Algorithm', 'levenberg-marquardt', 'MaxFunctionEvaluations',10^5, 'MaxIterations', 10^5, 'FunctionTolerance',10^-10, 'StepTolerance', 10^-10);
delta_Abs(:, 1) = data_new2(:, 1);
carrierT = carrier_T(1, 1);
fnh = @(x, e_p) EM_TA_wR1(x, e_p, z);
% calling the function now works without error...
fnh(x0, E_p) % but do you expect MATLAB to curve-fit NaNs ????
ans = 345x1
   NaN
   NaN
   NaN
   NaN
   NaN
   NaN
   NaN
   NaN
   NaN
   NaN
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
% You need to debug why your calculation produces NaNs:
out = lsqcurvefit(fnh, x0, E_p, delta_Abs(:, 1), lb, ub, optim_lsq);
Error using lsqncommon (line 35)
Objective function is returning Inf or NaN values at initial point. lsqcurvefit cannot continue.

Error in lsqcurvefit (line 322)
    lsqncommon(funfcn,xCurrent,lb,ub,options,defaultopt,optimgetFlag,caller,...
% Fitting function: Elliott's Model for Transient Absorption
function F = EM_TA_wR1(x, e_p, z)
P = z.p;
kB = 8.617333268*10^-5; % units: eV/ K
A1 = P(1,1);
A2 = P(1,2);
Eg = P(1,3);
Eb = P(1,4);
R = P(1,5);
g = P(1,6);
carrier_T = [1198.8, 816.7, 446.8, 328.7];
F = nan(size(e_p));
for i = numel(e_p)
	E_p = e_p(i);
	F(i) = x(5)*A1.*((2.*pi.*sqrt(x(2)))./E_p).*1/g.*(integral(@(E)sech(((E_p - E)./g)).*(1 + 10.*R.*(E - x(1)) + ...
		126.*(R).^2.*(E - x(1)).^2)./(1 - exp(-2.*pi.*sqrt(x(2)./(E - x(1))))), x(1), Inf, 'ArrayValued', 1)).*(1 - 1./(1 + exp((E_p - x(4))./(kB.*carrier_T(1,1))))).^2 - ...
		A1.*(2.*pi.*sqrt(Eb)/E_p).*(1/g).*...
		(integral(@(e)sech(((E_p - e)./g)).*(1 + 10.*R.*(e - Eg) + ...
		126.*(R).^2.*(e - Eg).^2)./(1 - exp(-2.*pi.*sqrt(Eb./(e - Eg)))), Eg, Inf, 'ArrayValued', 1)) + ...
		x(6).*A2.*(4.*pi.*(x(2)).^3/2).*1/x(3).*(...
		(1/1^3).*sech((E_p - x(1) + x(2)./1^2)./x(3)) + ...
		(1/2^3).*sech((E_p - x(1) + x(2)./2^2)./x(3)) + ...
		(1/3^3).*sech((E_p - x(1) + x(2)./3^2)./x(3)) + ...
		(1/4^3).*sech((E_p - x(1) + x(2)./4^2)./x(3)) + ...
		(1/5^3).*sech((E_p - x(1) + x(2)./5^2)./x(3)) + ...
		(1/6^3).*sech((E_p - x(1) + x(2)./6^2)./x(3)) + ...
		(1/7^3).*sech((E_p - x(1) + x(2)./7^2)./x(3))) - ...
		A2.*(4.*pi.*Eb.^3/2).*1/g.*(...
		(1./1.^3).*sech((E_p - Eg + Eb./1.^2)./g) + ...
		(1./2.^3).*sech((E_p - Eg + Eb./2.^2)./g) + ...
		(1./3.^3).*sech((E_p - Eg + Eb./3.^2)./g) + ...
		(1./4.^3).*sech((E_p - Eg + Eb./4.^2)./g) + ...
		(1./5.^3).*sech((E_p - Eg + Eb./5.^2)./g) + ...
		(1./6.^3).*sech((E_p - Eg + Eb./6.^2)./g) + ...
		(1./7.^3).*sech((E_p - Eg + Eb./7.^2)./g));
end
F = F(:);
end

Jack on 11 Jul 2024

Hi Stephen, I've made the amendments that you've suggested and now my code could run. Thanks so much!

Sign in to comment.

Not enough input arguments

0 Comments
Show -2 older comments Hide -2 older comments

Accepted Answer

2 Comments
Show None Hide None

More Answers (0)

Categories

Products

Release

Tags

Community Treasure Hunt

Not enough input arguments

0 Comments Show -2 older comments Hide -2 older comments

Accepted Answer

2 Comments Show None Hide None

More Answers (0)

Categories

Products

Release

Tags

See Also

Community Treasure Hunt

0 Comments
Show -2 older comments Hide -2 older comments

2 Comments
Show None Hide None