WHAT IS THE WRONG HERE?

I AM TRYING TO FIND ALL CELLS IN A WICH EQUAL B THE CODE :
for j=1:length(defs) % loop over Mdr of defib
querymdr=data2(:,1); % "A" save MDR numbers
y=alldata(:,1); % "B"
idx= find(y==querymdr); % FIND ALL CELLS WHICH IS EQUAL
it gives me an error in
idx= find(y==querymdr);
what was i write wrong?

3 Comments

What is the error message?
Is it correct that y will be a cell array? Is querymdr also going to be a cell array?
Or is querymdr going to be a numeric value and you want to find the cells consist of a scalar that is that value? Or is querymdr going to be a numeric value and you want to find the cells that contain the numeric value somewhere in their numeric array? Or ... there are other possibilities.
querymdr has 5*1 cells, y has 37*1 cells
i want to find all the cells in y that matched(has the same numeric value) with querymed.
thats the whole file... i choose 5 cells in the first column (left).
and want to know all the cell in the first coulmn (right) which = it
i have this two tables querymdr & idx2 :
i want to compare the fisrt two coulmns of them , and the multiple value copy column 6 of it only
i want to have the answer like this:
what i can do? any one has an idea?

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 Accepted Answer

querymdr = cellfun(@(C) C{1}, data2); %presuming the first entry is a scalar!
ally = cellfun(@(C) C{1}, alldata); %presuming the first entry is a scalar!
Now you have two numeric vectors to compare. What you would do from there would depend on whether you are expecting multiple matches for each entry.

5 Comments

yes i expect a multiple matches for any array. and that is the case i have.
for cell 2 in querymdr there are 3 matches in y and i want them all
for query_y in querymdr
locations = find(ally == query_y);
matchingcells = alldata(locations);
...
end
it gives me error in the first line
querymdr = cellfun(@(C) C{1}, data2);
ally = cellfun(@(C2) C2{1}, alldata)
What error message does it give you?
Please show
class(data2)
class(alldata);
the class of both is cell

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