Simbolic Toolbox: how to avoid conj() in matrix *

N=10;x=0:(N-1);
syms real r;
a=r.^(x),
b=r.^(-x),
M=b'*a

Result is

a =

[ 1, r, r^2, r^3, r^4, r^5, r^6, r^7, r^8, r^9]

b =

[ 1, 1/r, 1/r^2, 1/r^3, 1/r^4, 1/r^5, 1/r^6, 1/r^7, 1/r^8, 1/r^9]

M =

[           1,           r,           r^2,           r^3,           r^4,           r^5,           r^6,           r^7,           r^8,           r^9]
[   1/conj(r),   r/conj(r),   r^2/conj(r),   r^3/conj(r),   r^4/conj(r),   r^5/conj(r),   r^6/conj(r),   r^7/conj(r),   r^8/conj(r),   r^9/conj(r)]
[ 1/conj(r)^2, r/conj(r)^2, r^2/conj(r)^2, r^3/conj(r)^2, r^4/conj(r)^2, r^5/conj(r)^2, r^6/conj(r)^2, r^7/conj(r)^2, r^8/conj(r)^2, r^9/conj(r)^2]
[ 1/conj(r)^3, r/conj(r)^3, r^2/conj(r)^3, r^3/conj(r)^3, r^4/conj(r)^3, r^5/conj(r)^3, r^6/conj(r)^3, r^7/conj(r)^3, r^8/conj(r)^3, r^9/conj(r)^3]
[ 1/conj(r)^4, r/conj(r)^4, r^2/conj(r)^4, r^3/conj(r)^4, r^4/conj(r)^4, r^5/conj(r)^4, r^6/conj(r)^4, r^7/conj(r)^4, r^8/conj(r)^4, r^9/conj(r)^4]
[ 1/conj(r)^5, r/conj(r)^5, r^2/conj(r)^5, r^3/conj(r)^5, r^4/conj(r)^5, r^5/conj(r)^5, r^6/conj(r)^5, r^7/conj(r)^5, r^8/conj(r)^5, r^9/conj(r)^5]
[ 1/conj(r)^6, r/conj(r)^6, r^2/conj(r)^6, r^3/conj(r)^6, r^4/conj(r)^6, r^5/conj(r)^6, r^6/conj(r)^6, r^7/conj(r)^6, r^8/conj(r)^6, r^9/conj(r)^6]
[ 1/conj(r)^7, r/conj(r)^7, r^2/conj(r)^7, r^3/conj(r)^7, r^4/conj(r)^7, r^5/conj(r)^7, r^6/conj(r)^7, r^7/conj(r)^7, r^8/conj(r)^7, r^9/conj(r)^7]
[ 1/conj(r)^8, r/conj(r)^8, r^2/conj(r)^8, r^3/conj(r)^8, r^4/conj(r)^8, r^5/conj(r)^8, r^6/conj(r)^8, r^7/conj(r)^8, r^8/conj(r)^8, r^9/conj(r)^8]
[ 1/conj(r)^9, r/conj(r)^9, r^2/conj(r)^9, r^3/conj(r)^9, r^4/conj(r)^9, r^5/conj(r)^9, r^6/conj(r)^9, r^7/conj(r)^9, r^8/conj(r)^9, r^9/conj(r)^9]

Answer 1

[Andrei Bobrov]

try use

syms r real
...
M=b.'*a

[Igor]

Good,

but what in case of indeed complex r?

that is the complex conjuction appears after matrix *?

my question is more wide

[Andrei Bobrov]

use " .' " instead of " ' "

[Igor]

Yes!

operation ' is the reason, I forgot

[Marta Shelton]

To Bobrov: this simple thing was hugely useful. Million thanks!

[Vatsal Shah]

To Andrei Bobrov; Please explain the difference between operations " .' " and " ' ".

Thanks in advance.

[Steven Lord]

See this documentation page.

[Yildirim Dirik]

Many thanks for your help. For below case, how can I define the every variable as real in the variable vecor 'a' ?

a = sym('a',[1,12])';

[Yildirim Dirik]

Found it! a = sym('a',[1,12],'real')';

Answer 2

[moh ab]

hi my friends

i have problem in result of equetion .

in my code

syms te1 te2 ted1 ted2

q=[cos(te1+te2) -sin(te1+te2) 0;...

sin(te1+te2) cos(te1+te2) 0;...

0 0 1]

q1 =

[ -sin(te1 + te2), -cos(te1 + te2), 0]

[ cos(te1 + te2), -sin(te1 + te2), 0]

[ 0, 0, 0]

q2 =

[ -ted2*sin(te1 + te2), -ted2*cos(te1 + te2), 0]

[ ted2*cos(te1 + te2), -ted2*sin(te1 + te2), 0]

[ 0, 0, 0]

t=q1+q2

z=t*.q'

the z(1,1)=0

but in result of matlab show

sin(te1 + te2)*(ted1*cos(te1 + te2) + ted2*cos(te1 + te2)) - cos(te1 + te2)*(ted1*sin(te1 + te2) + ted2*sin(te1 + te2))

how can i fix it ?