Bit missing after circular shift

I have noticed that after performing circular shift, the bit after the shift value is missing.

 Shiftvalue = randi(2, n)

n is the max length of array

 X = circshift(A, [1, Shiftvalue])

Problem : if Shiftvalue is 25, then the 26th bit is missing. Please help.

[Azzi Abdelmalek]

Can you post an example?

[Amrita K]

Shiftvalue = 27
A=[1 0 1 1 0 1 1 0 0 1 0 0 0 1 1 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 0 0]

X=010001100001111111111011100 10110110

Answer 1

[Roger Stafford]

Your result can be accounted for if your A row vector is a string vector of 1's amd 0's except that its first element is a blank space character:

   A = ' 10110110010001100001111111111011100'  (<-- Corrected)
   X = circshift(A,[1,27]);
   X =  010001100001111111111011100 10110110

Note: The call for a shift of 1 in the rows does nothing to a row vector. Nevertheless you should really have 0 there to get zero shift in case you happen to deal with arrays with more than one row:

   X = circshift(A,[0,27]);

[Walter Roberson]

I think Roger meant

   A = ' 10110110010001100001111111111011100'

[Roger Stafford]

Yes, I did mean that. Thanks Walter.

[Amrita K]

Thank you Sir, it's working. Appreciate it.

Answer 2

[Image Analyst]

This works just as expected for me:

ShiftValue = 27
A=[9 0 1 1 0 1 1 0 0 1 0 0 0 1 1 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 0 0]
X = circshift(A, [0, ShiftValue])
% Element 1 (which is 9) should now be at element 28.
X(28)  % It is 9, just as expected!