Asked by Bob Hickish
on 31 Jan 2017

I am writing a script that creates an array (A) of vectors. The value of each vector is the set subscripts that describe it's position within the array. eg, for a three dimensional square array with side length 4:

A{1} = [1,1,1]

A{4} = [4,1,1]

A{9} = [1,1,3]

Each vector is then passed to another function which calculates my final result. eg,

results(i)=myfunction(A(i))

Im trying to automate the first stage, ie, assigning the value of the vector A{i} to be its subscript place within A. This will be variable on both the number of dimensions that A has and the side length (the sides are always the same length).

The method I have devised involves using ind2sub(). The number of outputs from in2sub is dependent on the dimensionality of the input matrix. To overcome this I am creating a character array with a variable for each dimension of A. eg for 3 dimensions.

vector_name='[x,y,z]';

and then concatenate it with the string '=ind2sub(size(results),i)' :

command_sting=strcat(vector_name,'ind2sub(size(results),i)')

so for my 3 dimension example command_string would store the character array:

command_string=

'[x,y,z]=ind2sub(size(results),i)'

I am then trying to use eval() to evaluate this statement but I get an error message:

eval(command_string)

Index exceeds matrix dimensions.

However if I type what is stored in command_string straight into the command line I do get the right result:

i=1

[x,y,z]=ind2sub(size(results),i)

x =

1

y =

1

etc.

Why is the eval(command _string) not working? If anyone has a more elegant solution than this use of eval() I'd be grateful to hear it.

Answer by Guillaume
on 31 Jan 2017

Edited by Guillaume
on 31 Jan 2017

Accepted Answer

You don't need to use eval to cope with varying number of outputs. Use cell arrays and their implicit conversion to comma-separated lists:

indices = cell(1, ndims(results)); %create a cell array the right size

[indices{:}] = ind2sub(size(results), someindex); %assign c-s-l output to cell array

indexvector = [indices{:}]; %convert cell array to vector.

Bob Hickish
on 31 Jan 2017

Thanks! Just what I was hoping for!

Stephen Cobeldick
on 31 Jan 2017

Note that ind2sub is a very simple function, and it is trivial to copy it and make your own version that returns a vector instead of separate output arguments (do NOT overwrite the original file).

Then you could avoid the whole bother altogether.

Jan
on 31 Jan 2017

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Answer by Adam
on 31 Jan 2017

[x, y, z] = ind2sub( [3,4], 9 );

works even though the size of the input is 2d, you just get z = 1. Likewise if you use n outputs you will just get 1 for those beyond the dimensionality of the input.

I would prefer this as an implementation personally, using the maximum dimensionality you will have. Possibly it may be better putting the results directly into an array rather than n named variables, but wither works.

Your code that comes after your eval would still have the problem of having to know what variables it needs to put into the A cell array so you might as well have all the variables there and ignore the ones not relevant for the given dimensionality.

Bob Hickish
on 31 Jan 2017

Adam
on 31 Jan 2017

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## Stephen Cobeldick (view profile)

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## Stephen Cobeldick (view profile)

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## Jan (view profile)

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