Error when using the function exprnd.

Hi everyone,
I got the following from using the function exprnd. I am not quite sure what went wrong, have anyone experienced this before? How do you troubleshoot it? Thanks in advance.
Error message:
Error using rand Input following 'like' must be a variable of a type that supports RAND. For example, double and single variables support RAND.
Error in exprnd (line 34) r = -mu .* log(rand(sizeOut, 'like', mu)); % == expinv(u, mu)
Thanks, SM

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on 11 Mar 2017

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