a problem about sprintf, array and concetnation

i need a hope about this code, there's a mistake but i just can't figured it out..

i need the result:

out2=

[SemenPadang vs persiwa, SemenPadang vs persipura, PSPS vs ... SemenPadang,  bye, Persisam vs semen padang;

PSPS vs Persipura, PSPS vs Persiwa, PSPS vs SemenPadang, bye, ...   

BontangFc vs PSPS ]

teams = {'SemenPadang','PSPS','Sriwijaya','Persija','PelitaJaya','Persib','Persijap','Persibo','Arema','Persema','Persela','Deltras','Persiba','PSM','BontangFC','Persisam','Persiwa','Persipura'};

out2 =

[17  18  -2   0  -3  -4   5   6  -7  -8   9  10  -11  -12  13  14   -15   -16;

18  17   1   0  -4  -3   6   5  -8  -7  10  9 -12 -11  14  13  -16   -15 ]

ab = cat(2, teams, teams);
[brs, klm]= size(out2);

for b2= 1:brs

      for k2= 1:klm

          if out2(b2, k2) > 0

              out2(b2, k2)= sprintf('%s vs %s\n', ab{b2}, ab{abs(out2(b2, k2))}); % when out2 is positive,   

          elseif out2(b2, k2) < 0

              out2(b2, k2)= sprintf('%s vs %s\n', ab{abs(out2(b2, k2))}, ab{b2}); % it work's on single elements

          else

              out2(b2, k2)= sprintf('bye');

          end

      end
  end

thx for attention and guidance..

[Jan]

Please format the code as explained in the "Markup help" link.

What exactly is the "mistake"? Is "[ semen padang vs ..." the wanted or the unwanted result and which format does this have? Is it a string?

[mashudi]

thx simon,

pardon me, i try to concatenate between string value of "teams" through array of "out2" so i can make an array result's "out2", the final purpose was i can put the results's displayed on uitable..

since i have no another solution, i just put those operation 'coz it work's on a single element's..

Answer 1

[Walter Roberson]

sprintf() results in strings, which are character arrays. You cannot store an entire character array into a single location of a numeric array such as out2. In order to store a character array into a location designated with just two subscripts, you have to be storing into a cell array, such as

out3{b2, k2} = sprintf('%s vs %s\n', ab{abs(out2(b2, k2))}, ab{b2});

[mashudi]

thx walter, it make another option for me, i'll tried it ..