I am trying to do the following:
t = [1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20]; %time = 1x20
heatflux = [2 3 5 7 9 11 12 13 14 19 24 14 12 13 20 21 11 23 18 19]; %heatflux = 1x20
fun = @(t) (heatflux).*t;
energy = integral (fun,0,20);
And I get this error:
Matrix dimensions must agree.
Error in HeatFlux>@(t)(heatflux).*t
Error in integralCalc/iterateScalarValued (line 314)
fx = FUN(t);
Error in integralCalc/vadapt (line 132)
[q,errbnd] = iterateScalarValued(u,tinterval,pathlen);
Error in integralCalc (line 75)
[q,errbnd] = vadapt(@AtoBInvTransform,interval);
Error in integral (line 88)
Q = integralCalc(fun,a,b,opstruct);
Error in HeatFlux (line 22)
energy = integral (fun,0,20)
Can someone point what I am doing wrong? Both t and heatflux have the same matrix dimension 1x20!

 Accepted Answer

Andrei Bobrov
Andrei Bobrov on 1 Jun 2017
Edited: Andrei Bobrov on 1 Jun 2017
>> t = [1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20]; %time = 1x20
heatflux = [2 3 5 7 9 11 12 13 14 19 24 14 12 13 20 21 11 23 18 19]; %heatflux = 1x20
energy = trapz(t,heatflux)
energy =
259.5000
>>

3 Comments

energy = trapz(t,heatflux);
Best wishes
Torsten.
Perfect! Thanks!
Thank you Torsten!
This my typo. I'm corrected.

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More Answers (1)

Torsten
Torsten on 1 Jun 2017
Use "trapz".
Best wishes
Torsten.

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