Make the x axis of a line plot vertical

I data saved in a cell array that I wish to plot in a vertical (portrait) axis in a gui window. The data is essentially a vertically binned matrix (the sum of each row in a single column). When I plot this data in the axis, the x axis is at the bottom, meaning all the data is squished into a narrow plot. My query is, how do I make the x axis vertical and the y axis horizontal? I have tried the simple plot(y,x) command but I did not specify x and y, the data is in a cell array so this does not work. Any help would be greatly appreciated

1 Comment

What do you mean by 'doesn't work'? You have to pull the data out of a cell array however you plot it so why is plot(y,x) and different to plot(x,y)?
You can rotate the axes through 90-degrees, but when I have done that it quickly gets confusing when giving instructions to the axes.

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 Accepted Answer

It would help to have some of your data and an example of the result you want. Without those, it is difficult to provide an exact solution.
One approach is to experiment with the view function to get the result you want.
Example
x = 1:10;
y = rand(1,10);
figure(1)
plot(x,y)
figure(2)
plot(x,y)
view([-90 90])
Here, figure(2) has the axes rotated.
EDIT
The correct result is:
view([90 -90])

5 Comments

My data is a large matrix which i then condense each row so that there is only a single column of data (sum(data, 2);) and then I plot this data. The figure two method you showed though does seem to work. I had tried this before but with [0 90] rather than -90. One problem with it is that it has the new x axis in descending order, going from 200 to 0 left to right. This is not a huge problem but I was wondering is there a fix for it to your knowledge?
I fixed the problem, thanks Star Strider
As always, my pleasure.
My apologies for the glitch. I didn’t notice that earlier. I got the correct result with:
view([90 -90])
Yeah thats' how I did it
Great minds think on the same lines ...
I posted my previous Comment to be sure I fully resolved your Question, for the benefit of others who will refer to this thread.
I also edited my original Answer to include it.

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