How to print size of array?

The array size need to monitor. It's simple and effective with size(x) but no name or location. It would be nice to print if out this way:
fprintf(' size(xyz) at location 123 is [%d %d %d] \n',size(xyz));
because size(xyz) is "unknown" and how to write [%d %d %d] to print size(xyz) in one row?

Answers (2)

>> A = rand(2, 3, 1, 4);
>> fprintf('size(A) is %s\n', mat2str(size(A)))
or
>> A = rand(2, 3, 1, 4);
>> fprintf('size(A) is [%s]\n', int2str(size(A)))
Note that the spacing between the elements of the size may be a little different for those two approaches.
John - is xyz your 3D array? If so, then try
fprintf(' size(xyz) at location 123 is [%d %d %d] \n',size(xyz, 1), size(xyz, 2), size(xyz, 3));

2 Comments

Dimension is unknown. That's the problem!
then consider using ndims with
xyz = randi(255,12,13,14);
fprintf('size(xyz) at location 123 is [');
for k=1:ndims(xyz);
fprintf(' %d',size(xyz, k));
end
fprintf(']\n');
or
fprintf('size(xyz) [');
fprintf('%d ',size(xyz)');
fprintf(']\n');
Or do you have a requirement that stats that you can only print this in one line?

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Asked:

on 11 Jul 2017

Answered:

on 11 Jul 2017

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