Why does "mapstd" returns unexpected dimensions when I apply it to a new sample data?

10 views (last 30 days)
Why does "mapstd" returns unexpected dimensions when I apply it to a new sample data?
I have 4 sample data, each containing 2 predictor variables:
 
>> X = [ 2 1;
5 0;
3 0;
4 2];
I standardize this using "mapstd" as follow:
 
>> [Xnew, PS] = mapstd(X);
However, when I try standardizing a single new sample data "Xtest", it produces a 4x2 array instead of 1x2 array:
>> Xtest = [2 3];
>> XtestNew = mapstd('apply', Xtest, PS)
XtestNew =
0.7071 2.1213
-0.1414 0.1414
0.2357 0.7071
-0.7071 0

Accepted Answer

MathWorks Support Team
MathWorks Support Team on 28 Dec 2017
The "mapstd" function normalizes the input data row-wise (horizontally). Therefore, with your current implementation, you are actually normalizing each sample individually since you are putting your data one above the other in the following format (4 rows x 2 columns):
X =
[ sample1
sample2
sample3
sample4 ]
 In order to use "mapstd" function to normalize each of your 2 predictor variables, you would need to store your data in the following format (2 row x 4 columns):
X = [ sample1 sample2 sample3 sample4]
 Then, you can use "mapstd" function and get 2 means and 2 standard deviations (one for each predictor variable).
 Making the necessary modification to the original data:
 
>> X = X'; % store sample column by column instead
>> [Xnew, PS] = mapstd(X);
>> XtestNew = mapstd('apply', Xtest, PS);

More Answers (0)

Categories

Find more on Specialized Power Systems in Help Center and File Exchange

Tags

Products


Release

R2017b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!