I've been used the following commands to plot a feather plot:
(OBS: u and v are the components of the wind, and the vectors date are: year, month and day)
t = datenum(year,month,day);
feather(u,v)
hold on
plot(t, zeros(size(u)))
datetick('x','dd/mm/yyyy','keepticks', 'keeplimits')
But that isn't working very well.
I'm getting the following figure:
I've been tried to use the quiver plot, with the following commands:
t = datenum(year,month,day);
quiver(t, zeros(size(u)), u, v);
datetick('x','dd/mm/yyyy','keepticks', 'keeplimits')
with that I get the following image (It seems better, but the intensity of the winds are wrong, so I guess that the quiver function don't is correct for the case):
Repare that using the feather function the intensity of the wind is plotted correctly, but the graph and the values of the date in the X axis is wrong, meanwhile, whith the quiver the date is correct and the plot is correct, but the intensity is wrong.
Can someone help me to find the error? Is there another way to plot that information?

2 Comments

The year values seem wrong. The maximum year in the first plot is 2190, and in the second, 2020.
Are you plotting historical values, or predicting future values?
Yes, they are wrong, I'm plotting historical values, with the first plot the years are completly wrong, the correct time period is from jan/1998 to jan/2018, however, the second one uses the same date vector and the year is plotted correctly. That is one of the problems that I want to solve.

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 Accepted Answer

Apparently, feather and datetick don’t work and play well together.
This workaround is the best I can do:
t = datenum([1998 01 01]):datenum([2018 01 01]);
u = rand(size(t));
v = rand(size(t));
figure
feather(u,v)
set(gca, 'XLim',[0 numel(u)]) % Set X-Axis Limits
xt = get(gca,'XTick') % Get X-Tick Values
xt(1) = 1;
txt = t(xt); % Define ‘t’ Using ‘xt’
set(gca, 'XTick',xt, 'XTickLabel',datestr(txt,'dd/mm/yyyy'), 'XTickLabelRotation',30)
I rotated the tick labels so they wouldn’t crash into each other.
Experiment to get the result you want.

4 Comments

Robson Passos
Robson Passos on 1 Apr 2018
Edited: Robson Passos on 1 Apr 2018
Thank you very much, It works, I got the following figure:
I couldn't rotate the label because I'm using Matlab 2013a. The last tick of the x axis doesn't appear, do you know how I can fix it?
As always, my pleasure.
I don’t have access to R2013a, so you will need to test this. It works in R2018a:
t = datenum([1998 01 01]):datenum([2018 01 01]);
u = rand(size(t));
v = rand(size(t));
figure
feather(u,v)
set(gca, 'XLim',[0 numel(u)]) % Set X-Axis Limits
% xt = get(gca,'XTick') % Get X-Tick Values
Nt = 7; % Set Number Of X-Ticks
xt = linspace(1, numel(t), Nt); % Create New X-Tick Values
xt = floor(xt); % Use X-Tick Values As Subscripts
txt = t(xt); % Define ‘t’ Using ‘xt’
set(gca, 'XTick',xt, 'XTickLabel',datestr(txt,'dd/mm/yyyy'), 'XTickLabelRotation',30)
It creates a new tick vector that will completely span the ‘t’ vector. You can control the number of ticks with ‘Nt’.
If my Answer helped you solve your problem, please Accept it!
It worked perfectly, thank you very much for your help. :)
As always, my pleasure!
This is an interesting problem!

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More Answers (1)

Benjamin Gillard
Benjamin Gillard on 16 Dec 2019
This code is great!!
it did help me a lot and save me of a potential brain damage.
Work on 2019b.
Thank you very much,

1 Comment

My pleasure!
A Vote would be appreciated.

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