move element in array

Hi,

I have an array of n elements, let's say for example:

[0 1 2 3 4 5]

I want to move the position of one of the elements left or right by one, let's say:

[0 1 2 4 3 5]

How can I do this? Does indexing help?

[Stephen23]

Just use indexing:

>> V = [0,1,2,3,4,5];
>> V([5,4]) = V([4,5])
V =
   0   1   2   4   3   5

[thiago rech]

Wau! Thank you!

Answer 1

[Navid Mohammadzadeh]

Why do not use "circshift" command?

Look: A =

     1
     2
     3
     4
     5
     6
     7
     8
     9
    10

Y = circshift(A,3)

Y =

     8
     9
    10
     1
     2
     3
     4
     5
     6
     7

[Stephen23]

@Navid Mohammadzadeh: because circshift does not change the position of one element, as the example in the question shows.

[thiago rech]

Maybe that was not the answer he was looking for, but it helped me with something else really cool.

Thanks!

Answer 2

[Christoph]

Hi,

your problem sounds wired. For what reason do you want to switch the postion of only two elements in an array?

Nevertheless I guess indexing is the only way to switch the positon of two elements. Also you need a temporary variable to store one of the objects. My solution would look like:

X = [1 2 3 4 5]; temp = X(3); X(3) = X(4); X(4) =temp;

If you need more than one time write an function with X and i (element you want to switch) as input argument and x as outputargument.

Kind regrads, CN

[darksideofthemoon101]

Thanks Christoph. I'm modelling a deck of cards and want to move the position of one card in the array, keeping the rest of the cards in their relative places. A function may be useful.

[Christoph]

Hi Moon,

intresting idea. I'll try to write this function at the evening if the todays soccer game is not that interesting ;)

[Christoph]

Just thought a further minute about your problem. I guess I would modelling mixing cards in a different way. I would divide the vector at a random position and put the first stack behind the second....that should look like this:

pos = randi([1, numberofcards-1])

stack = [stack(pos+1,end),stack(1:pos)];

put this it in a for loop and you modelled the perfect card mixer