Need to define an array
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I need an array that has 98 entries. the first value is 1000 and the second to last is 100. the values inbetween vary linearly but alternate with zeros.
[1000, 0, ~990,0.... 100,0]
3 Comments
Stephan
on 26 Feb 2019
sounds like a homework. please provide your attempt so far.
Thomas Holmes
on 26 Feb 2019
madhan ravi
on 27 Feb 2019
What?
Answers (2)
Hi,
note that the length of T is 49 - not 98.
The proper way to do this is:
Fg=zeros(1,98);
Fg(1:2:end) = linspace(1000,100,49)
Thats all.
Best regards
Stephan
@Thomas: The problem is still unclear.
"the first value is 1000 and the second to last is 100" - this means:
R = [1000, repmat(100, 1, 97)]
"the values inbetween vary linearly but alternate with zeros" - this is not clear: inbetween what?
The output should have 98 elements, while the first and the last is non-zero and the others are zero. This is not possible, because you need an odd number of elements for this.
You have shown some effort. So although I assume it is a homework, it is worth to assist you. Maybe all you want can be done in a single line:
Result(1:2:97) = linspace(1000, 100, 49);
But te result has 97 elements. There is no way for alternating zeros and non-zeros with leading and trailing non-zero and and even number of elements. Maybe with a trailing 0 (see Stephan's comment) pre-allocate the output at first:
Result = zeros(1, 98);
Or with your loop:
T = linspace(1000, 100, 49)
Fg = zeros(1, 98);
for k = 1:length(T) % Not length(Fg)
Fg(k * 2 - 1) = T(k);
end
Again, the last element is 0 then.
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