Looping problem in this program

Vs=1;
rs=1;
rl=1;
r=10;
ll=2e-3;
VRi(n)=0;
VLi(n)=0;
l=5e-3;
c=10e-6;
g=1;
zo=sqrt(l/c);
t=sqrt(l*c);
zl=(2*ll)/t;

%VOLTAGE AND CURRENT
%n=1

V1=((Vs/rs)+((2*VRi1))/(r+zo))/((1/rs)+(1/(r+zo)));
i1=((V1-(2*VRi1))/(r+zo));
VR1=(2*VRi1)+(i1*zo);

%n=2,....,n-1 (i.e n=2)   
 &

V2=(((2*VLi2/(zo))+((2*VRi2)/(zo+r)))/((1/zo)+(1/(r+zo)+(g))));  % Every n of  VLi n =VRi n is equal to zero (how to define it)
i2=((V2-(2*VRi2)/(r+zo)));
VL2=V2;
VR2=(2*VRi2)+(i2*zo);
&
%n=n(i.e n=11)

V11=(((2*VL11/(zo))+(2*Vi/(rl+zl)))/((1/zo)+(1/(zl+rl)+(g))));
IL=((V11-(2*Vi))/(rl+zl));
V=(2*Vi)+(il*zl);

%REFLECTED VOLTAGES
%n=1

VRr1=VR1-VRi1;

%n=2,....,n-1 (i.e n=2)
&
VLr2=VL2-VLi2;
VRr2=VR2-VRi2;
&
%n=n(i.e n=11)

VLr11=V11-VLi11;

%INCIDENT VOLTAGES
%n=1

VRi1=VLr2;

%n=2,3,....,n-1 (i.e n=2)
&
VLi2=VRr1;
VRi2=VLr3;
&
%n=n(i.e n=11)

VLi11=VRr10;
Vi=-Vr;

The Ampersand symbol (&), from start to end, has to be put into a loop. How do I do it?

[Geoff Hayes]

Venkatkumar - please clarify what you mean by The Ampersand symbol (&), from start to end, has to be put into a loop. Also, where is n defined? Is that the iterating variable in your for loop? Can you show all of your code?

[Venkatkumar M]

Given code is full code

VLi(n)=VRr(n-1);

VRi(n)=VLr(n+1);

i just need this section (and the section with &)to be looped for n=2,3,...,n-1

Answer 1

[Image Analyst]

Put

for k = 1 : numIterations

before the code that you want to be in the loop, and

end

after the code. numIterations is how many times you want to do the loop. Please look at

https://matlabacademy.mathworks.com/

and this link also:

Debugging Tutorials

I have no idea what the ampersands are supposed to do so it's difficult to advise you further. For example, maybe

VRi1=VLr2;
%n=2,3,....,n-1 (i.e n=2)
&
VLi2=VRr1;
VRi2=VLr3;
&
%n=n(i.e n=11)
VLi11=VRr10;

means

result = VRi1 == VLr2 && ...
VLi2 == VRr1 && ...
VRi2 == VLr3 && ...
VLi11 == VRr10;

but I really have no idea what your intent is.

And for testing equality of floating point numbers, See the FAQ

[Venkatkumar M]

VLi(n)=VRr(n-1);
VRi(n)=VLr(n+1);

i just need this to be looped for n=2,3,...,n-1

And

In this section Every n of VLin =VRin is equal to zero (how to define it)

Vn=(((2*VLin/(zo))+((2*VRin)/(zo+r)))/((1/zo)+(1/(r+zo)+(g))));  
in=((Vn-(2*VRin)/(r+zo)));
VLn=Vn;
VRn=(2*VRin)+(i2*zo);

[Image Analyst]

Try:

for n = 2 : length(VLi)
        VLi(n)=VRr(n-1);
        VRi(n)=VLr(n+1);
end

As for "Every n of VLin =VRin is equal to zero (how to define it)" I don't have the slightest idea what that means. Perhaps get someone else to look over the wording to help you epxlain it better.

[Venkatkumar M]

Compare img with the first program

now do u able get it?