Write a function called picker that takes three input arguments called condition, in1 and in2 in this order. The argument condition is a logical. If it is true, the function assigns the value of in1 to the output argument out, otherwise, it assigns

function [cd,a,b]=picker(cd,a,b);
if picker(a<b,a,b)
    fprintf('out=a');
else
    fprintf('out=b')
end

[evan muas]

This is my solution. If you assign cond==1 or true, it still works well.

function out= picker(cond,in1,in2)
if cond==1
    out=in1;
else
    out=in2;
end

[Guillaume]

When cond is logical, if cond == 1 is just a slower way of doing if cond.

cond == 1 converts the logical to a double, compare that double to one to return the exact same logical value you started with.

Answer 1

[Stephen Cobeldick]

function [cd,a,b]=picker(cd,a,b);
if picker(a<b,a,b)
    fprintf('out=a');
else
    fprintf('out=b')
end

Your function ignores the first input entirely, and then for no obvious reason it recursively calls itself, providing its first input (which is ignored anyway) as being the output of the comparison a<b (a comparison which is not mentioned anywhere in your assignment). Then you provide three outputs from the function, none of which are the one output that the assignment requested. For no obvious reason you print some data to screen, which is nice, but is irrelevant for the assignment that you were actually given.

You need to read the assignment, understand what it requests, and then implement that... in fact your assignment is so clearly explained, it almost does all of your work for you:

function out = picker(cond,in1,in2);
if ???
    out = ???;
else
    out = ???;
end

I left you three very simple things for you to complete. (hint: use each input variable once).

[Moeez ur Rehman Qureshi]

I have rewritten my function but it is giving me out=in1 for both cases.

function out = picker(cond,in1,in2);
if true
    out = in1;
else 
    out = in2;
end

[Guillaume]

Well of course. What else did you expect?

if true
    dosomething
else
    dosomethingelse
end

is always going to execute dosomething since you're explicitly setting the if condition to true.

[Stephen Cobeldick]

@Moeez ur Rehman Qureshi: much better, but you should read my answer "use each input variable once": how many inputs does the function have, and how many have you used?

Answer 2

[Chech Joseph]

function out = picker(condition,int1,int2)
   condition = int1 > int2
   if condition == 1
       out = int1
   elseif condition == 0
       out = int2
   else
       return
   end

still not pasing both tests. Why?

[Steven Lord]

Your function ignores the value its caller passes into it as the first input, throwing the user's input away and replacing it with the result of "int1 > int2". Is that how your assignment states the function should behave?

I don't know if your assignment is different from the one posted by Moeez ur Rehman Qureshi but if it's the same no, your function does not behave the way the assignment states it should.

[Rik]

Also, this is not an answer, but a comment or a question. You should have put it in the comment section.

Answer 3

[Ahmed J. Abougarair]

function out = picker(condition,int1,int2)
y=logical(condition)        
if  y==1
    out = int1;
else
    out = int2;
end
end

[Stephen Cobeldick]

See: https://www.mathworks.com/matlabcentral/answers/471197-write-a-function-called-picker-that-takes-three-input-arguments-called-condition-in1-and-in2-in-thi#comment_776284

[Rik]

Why are you posting complete solutions to homework questions?

And if y is already a logical, why to you compare it to 1?

[Anurag Verma]

function out=picker(condition,in1,in2)
if condition==true
    in1<in2 && in2>in1
    out=in1
else condition==false
    in2>in1||in2==in1
    out=in2
end

Answer 4

[Vishal Natraj]

function[out] = picker(condition, in1, in2)
if %fill the conditon on your own
out = % ???;
else 
out = %???
end

[Vishal Natraj]

this in fact a VERY straightforward question :-)

[Rik]

Why are you posting such a nearly complete solution to a homework question?

[Vishal Natraj]

changed it mate. Sorry (:

[Jun Choi]

function out = picker(condition,in1,in2)

if condition == 1

out=fprintf('%d\n',in1)

else

out=fprintf('%d\n',in2)

end

@Vishal, Thank you for the explanation. I understand what the correct answer is. Then, I tried to come up with different form of answer above. What is wrong this code?

[Stephen Cobeldick]

@Jun Choi: the fprintf documentation explains that its output is "...the number of bytes that fprintf writes". Is that what your assignment requests that your function output should be?

Does the assignment require that your function should print something to the command window?

Answer 5

[sourab sarkar]

function out=picker(cdn,in1,in2)
  if(cdn ==1)
        out=in1;
  else
        out=in2;
end
---------------------

Answer 6

[sourab sarkar]

As the assignment example explains that the user enters the arguments i.e the condition and value of in1 and in2.So,task is to write a program that can check for all conditions given by the user and produce the aprocreate output.

Answer 7

[Roweida Bawab]

This is how I solved it

function out = picker (condition, in1, in2)
if condition == true
    out = in1;
else out = in2;
    return
end

[Stephen Cobeldick]

Writing condition == true is not required, as explained in this comment:

https://www.mathworks.com/matlabcentral/answers/471197-write-a-function-called-picker-that-takes-three-input-arguments-called-condition-in1-and-in2-in-thi#comment_776284

The return is not required.

It would be much clearer to write out = in2; on its own line.

[Roweida Bawab]

Noted. Thank you :)

Answer 8

[Anurag Verma]

function out=picker(condition,in1,in2)
if condition==true
    in1<in2 && in2>in1
    out=in1
else condition==false
    in2>in1||in2==in1
    out=in2
end

this is the code that should be used and do not copy paste plz understand and do.

[Stephen Cobeldick]

function out=picker(condition,in1,in2)
if condition==true % superfluous "==true", see Guillaume's comment below the question
    in1<in2 && in2>in1 % serves no functional purpose
    out=in1 % probably should use trailing semi-colon
else condition==false % superfluous "condition=false", should be simple "else"
    in2>in1||in2==in1 % serves no functional purpose
    out=in2 % probably should use trailing semi-colon
end

Note that the syntax

else X

is actually equivalent to

else
    X

where X is simply displayed and serves no functional purpose.

Answer 9

[AYUSH MISHRA]

function out=picker(condition,in1,in2)
    if condition==true
        out=in1;
    else out=in2;
end

SOLUTION :

picker(true,1,2)

ans =

1

picker(false,1,2)

ans =

2

Answer 10

[ROHAN SUTRADHAR]

function out = picker(condition,in1,in2)
if condition==0
    out = in2;
else
    out = in1;
end