Could anyone help me to solve the issue.

I am having matrix

   A=[1     2;
     2     3;
     2     4]

when i use the command

NN = num2cell(num2cell(A),2)
partdisp(NN)

i am getting the result as

NN = 

    {1x2 cell}
    {1x2 cell}
    {1x2 cell}

The formation of clusters :

{1} {2} 
{2} {3} 
{2} {4}

but i need to have the result in the following manner

NN = 

    {1x1 cell}
    {1x1 cell}
    {1x1 cell}
    

The formation of clusters :

{1 2} 
{2 3} 
{2 4}

could anyone please help me on it.

Answer 1

[madhan ravi]

NN = num2cell(num2cell(A,2),2)

[jaah navi]

i am having the matrix

A =[ 2 3 4 1 5 6 7 ;

1 4 3 2 5 6 7 ;

2 4 3 1 5 6 7;

3 4 1 2 5 6 7]

If i use the command

NN = num2cell(num2cell(A,2),2)

all are getting grouped together

NN ={1x1 cell}

{1x1 cell}

{1x1 cell}

{1x1 cell}

if i use the command NN = num2cell(num2cell(A),2) all are separate

NN ={1x7 cell}

{1x7 cell}

{1x7 cell}

{1x7 cell}

Could you help me how it can be done for the criteria {2 3}{4 1 5} {6} {7}

to have first two numbers present in first row are grouped together,followed by next three numbers grouped together ,followed by next one number alone ,followed by the last number alone

[madhan ravi]

That question is different from what you asked originally.

[jaah navi]

ok.But is there any other way to have random combinations like {2 3}{4 1 5} {6} {7} other than { 2 3 4 1 5 6 7} or {2} {3} {4} {1} {5} {6} {7}.

[madhan ravi]

mat2cell(A,[1,1,1],[2,3,1,1]) % see the documentation and learn how to use it

Answer 2

[Fabio Freschi]

For your case

NN = mat2cell(A,[1 1 1],2)

A bit more general

NN = mat2cell(A,ones(size(A,1),1),size(A,2))

[madhan ravi]

Isn’t that what Rik posted earlier to this answer?

[Fabio Freschi]

The time difference is a few minutes (seconds?): I haven't seen Rik's answer before posting.

[Rik]

I believe it was about 5 minutes, which happens a lot if you open a recent question and open a few tabs at once to answer them in a batch. One time there were already 4 answers (3 of which way better than mine) by the time I had found a working solution.

[Fabio Freschi]

Not my case. Just running the code before posting

[Adam]

Yeah, even just opening a question and typing your answer can take long enough that when it's posted there are 2 or 3 other answers too. It's perfectly fine though.