How can i get sub matrices with using for loop
Show older comments
Hello everyone
I have a matrix A as:
A=[1
1
1
1
1
1
1
1
1
1
2
2
2
2
2
2
2
2
2
2
3
3
3
3
3
4
4
4
4
4
5
5
5
5
5
6
6
6
6
6
7
7
7
7
7
7
7
7
7
7
8
8
8
8
8
8
8
8
8
8
9
9
9
9
9
9
9
9
9
9
10
10
10
10
10
10
10
10
10
10
11
11
11
11
11
11
11
11
11
11
12
12
12
12
12
12
12
12
12
12]
I get unique(A) as 12. And then i want to get new matrices as
for i=1, A(1) as row which is equal to i. And for i=2, A(2) as row which is equal to i.............for i=12 A(12) as rows which is equal to i.
For example:
A(1)=[1
1
1
1
1
1
1
1
1
1]
A(2)=[2
2
2
2
2
2
2
2
2
2]
A(3)=[3
3
3
3
3]
........
A(12)=[12
12
12
12
12
12
12
12
12
12]
How can i do this with using for loop or another way? I want to get new matrices as A(1) to A(12).
Accepted Answer
More Answers (1)
madhan ravi
on 17 Sep 2019
a=arrayfun(@(x)A(A==unique(x)),A,'un',0)
celldisp(a)
If you’re goal is simply to create A with repetitions of 10 then it’s simply:
A = num2cell(repmat(1:12,10,1),1)
celldisp(A)
3 Comments
Mooner Land
on 17 Sep 2019
madhan ravi
on 18 Sep 2019
How's this related to the question you originally asked?
Mooner Land
on 18 Sep 2019
Categories
Find more on Loops and Conditional Statements in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!