creating matrix from a vector

let's suppose I have this vector

v=[0; 0; 4; 6]

and I want to create a matrix such that

X=[0,0,0; 0,0,0; 4,4,0; 6,6,6]

does it exist a way through for cylce to obtain a result like this?

My aim is to create such a matrix in order to discount coupon premiums for different bonds all in a matrix (X), so the repetition of the values are the number of frequency of each cashflow. as in the example:

first two elements of the vector v represent zero coupon, so the repetition will be zero

the third one is 4 and it provides 2 cashflows ->(Maturity=1 year; freq=0.5 -> (1/0.5))

the last one is 6 and provide 3 cashflows ->(Maturity=1.5; freq=0.5 -> (1.5/0.5))

Answer 1

[Stephen23]

>> v = [0,0,4,6]
v =
   0   0   4   6
>> n = ceil(v/2);
>> w = 1:max(n);
>> m = bsxfun(@times,v,bsxfun(@le,w(:),n))
m =
   0   0   4   6
   0   0   4   6
   0   0   0   6

Or for MATLAB versions >=R2016b:

m = v .* (w(:)<=n)

[Tommaso Decataldo]

Thank you that’s great

Answer 2

[KALYAN ACHARJYA]

let's suppose I have this vector

v=[0; 0; 4; 6]

and I want to create a matrix such that

X=[0,0,0; 0,0,0; 4,4,0; 6,6,6]  
% it may be..........^4 

One way:

v=[0; 0; 4; 6];
X=reshape(repelem(v,3),[3,4])'

Rest text lines, I didn't go through, generally I avoid to read long texts.

Hope you get the first answer.

[Tommaso Decataldo]

This is not bad but my real problem is that

X=[0,0,0; 0,0,0; 4,4,0; 6,6,6]

% it may be ..........^4 (not)

the matrix should be exactly like I wrote.