continue or break a loop from a function

Hello,

Is it possible to continue a caller loop from the function called ?

Example :

The caller is :

for i =1:5
    test(i)
end

And the function is :

function test(i)
    if i == 5
        evalin('caller','continue')
    end
end

and the result is :

Error using test (line 3)

Error: A CONTINUE may only be used within a FOR or WHILE loop.

Error in Untitled3 (line 2)

test(i)

Answer 1

[Mehmed Saad]

You can signal that using flags

for i =1:5
   flag= test(i);
   if(flag)
       continue;
   end
end

And the function is :

function flag = test(i)
    if i == 5
   flag = true;
    else
   flag = false;
    end
end

[Ziad Sliti]

Yes thank you for your response, it's what I already did but I wanted to know if there was a "better" solution whitout creating a flag, and also to understand why "evalin" doesn't work.

[Mehmed Saad]

Try just runing a for loop, and enter a break point at iteration 3

Now Try typing break or continue on command prompt, it will give error

Error: A BREAK statement appeared outside of a loop. Use RETURN instead.

because you are not inside for loop due to breakpoint

Similar is the issue with eval or evalin function as when the evaluate you expression, it is not inside the for loop