Why does a Boolean XOR block become a bitwise operation in generated C code?
Show older comments
When I generate code from a Boolean XOR block, it becomes a bitwise operation in the generated C code. Why is this the case, and are there any workarounds?
Accepted Answer
MathWorks Support Team
on 18 Oct 2024
Edited: MathWorks Support Team
on 14 Oct 2021
0 votes
The "^" operator that is produced as generated code for the Logical XOR block is expected behavior since there is no true Boolean XOR operator in C.
If you wish to generate the relation operator "!=" instead, in the place of the Logical Operator XOR block you can use the Relational Operator block and select "~=".
More Answers (0)
Categories
Find more on Texas Instruments C2000 Processors in Help Center and File Exchange
on 9 Apr 2020
on 14 Oct 2021
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
