Why does a Boolean XOR block become a bitwise operation in generated C code?

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When I generate code from a Boolean XOR block, it becomes a bitwise operation in the generated C code. Why is this the case, and are there any workarounds?

Accepted Answer

MathWorks Support Team
MathWorks Support Team on 18 Oct 2024
Edited: MathWorks Support Team on 14 Oct 2021
The "^" operator that is produced as generated code for the Logical XOR block is expected behavior since there is no true Boolean XOR operator in C.
If you wish to generate the relation operator "!=" instead, in the place of the Logical Operator XOR block you can use the Relational Operator block and select "~=".

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