Error for exceeding the loop

Hi,

I have d = {[5:10] [20:30]}; e = [1 2 7 8 9 11 12 15 16 22 25 30 35 40 45]; I want to extract values from e which falls into vectors of d.

Result = { [7 8 9] [22 25 30] } because 7, 8 and 9 are within 5 and 10; 22, 25 and 30 are within 20 and 30.

The code I tried gave what I want but when i == 3, the error happened. How can I stop j loop when all vectors in d have been checked. Thank you!

clc; clear; close all
d = {[5:10] [20:30]};
e = [1 2 7 8 9 11 12 15 16 22 25 30 35 40 45];
E = length(e);
D = length(d);

for i = 1:D    
    while j <= max(d{end})
        for j = 1:E
            if e(j) >= min(d{i})     
                a(i) = e(j);
                for k = j+1:E
                    if e(k) > max(d{i})
                    b(i) = e(k-1);           
                    want{i} = [e(j:k-1)]; 
                    
                       if ~isempty(b(i)) 
                           j=k; 
                           i=i+1;
                           break; 
                       end   
                    end                
                  end             
            end         
     end       
               
    end
end

Answer 1

[KSSV]

Why you have made code that complex? It is a simple task. You can use intersect.

d = {[5:10] [20:30]};
e = [1 2 7 8 9 11 12 15 16 22 25 30 35 40 45];
N = length(d) ;
result = cell(N,1) ; 
for i = 1:N
  iwant{i} = intersect(e,d{i}) ;
end

[HYZ]

thank you!

[HYZ]

Sorry ... I didn't think far. my real data are something like

d = {[5:10] [20:30]}; e = [1 2 7.5 8.5 9.5 11 12 15 16 22.5 25.5 30 35 40 45];

the elements in e might not be exactly same as in d. they are juz within the range of each vector in d.

Could you advise? thanks.

[KSSV]

What is expected output here?

[HYZ]

Output will be { [7.5 8.5 9.5] [22.5 25.5 30]}. thanks

[KSSV]

Have a look on knnsearch, ismembertol.

[HYZ]

I used 'find' to do it. Anyway thanks. I learnt "intercept"

clc; clear; close all
d = {[5:10] [20:30]};
e = [1 2 7.5 8.5 9.5 11 12 15 16 22.5 25.5 30 35 40 45];
D = length(d);
iwant = cell (1,D);
   
for i = 1:D 
    loc {i} = find(e >= min(d{i}) & e <= max(d{i}));
   iwant{i} = [e(loc{i})];
end