multiplying vectors (easy one!)

Sorry guys, an easy question:

how do I evaluete this function in the interval

x=[-0.2,0.8]

the function is f = 2.2785*T_0(x) - 0.2142*T_1(x) - 0.3595*T_2(x) - 0.1793*T_3(x) + 0.1810*T_4(x)

where T_k(x)=cos*(k*cos^-1(x))

c =

    2.2785
   -0.2142
   -0.3595
   -0.1793
    0.1810
    

Answer 1

[KSSV]

m = 100 ; 
x = linspace(-0.2,0.8,m) ;

Evaluate the function for every value of x. Read about element by element operations.

[Paul Rogers]

x = [-0.2:0.01:0.8];

[KSSV]

Yes you can use that too.....two ways

1. Fix the number of discretozations use linspace
2. Fix the step size and ise : .

[Paul Rogers]

thanks, but how do I write the rest?

f(x=0)=2.2785*T_0(x) - 0.2142*T_1(x) - 0.3595*T_2(x) - 0.1793*T_3(x) + 0.1810*T_4(x)

where for x=0 (i.e)

T_0(x=0)=cos*(0*cos^-1(x))

T_1(x=0)=cos*(1*cos^-1(x))

T_2(x=0)=cos*(2*cos^-1(x))

T_3(x=0)=cos*(3*cos^-1(x))

T_4(x=0)=cos*(4*cos^-1(x))

or x=-0.2

T_0(x=-0.2)=cos*(0*cos^-1(x))

T_1(x=-0.2)=cos*(1*cos^-1(x))

T_2(x=-0.2)=cos*(2*cos^-1(x))

T_3(x=-0.2)=cos*(3*cos^-1(x))

T_4(x=-0.2)=cos*(4*cos^-1(x))

c =
    2.2785
   -0.2142
   -0.3595
   -0.1793
    0.1810

and

x = [-0.2:0.01:0.8];