MATLAB code find factorial of n num
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Murathan Cuya
on 18 Jun 2020
Commented: Walter Roberson
on 18 Oct 2023
can you please Write a MATLAB code to Find factorial of a given number N?
3 Comments
Ahmet Zahit Akpinar
on 10 Mar 2022
I made it for 10! but you can change 10 by any value
n=1; i=1;
while i<=10
n=n*i;
i=i+1;
fprintf('n=%d\n')
end
Accepted Answer
Nipun Agarwal
on 18 Jun 2020
Hey,
The factorial of a number is calculated as
F(n) = (n-1)*(n-2)*(n-3)…….1 and F(0) = 1 always;
So we start from the right most side like F(p) where p = 1 initially and keep incrementing the value of p till n; The resultant value is your answer. I have written the function with variable n. replace n with any integer to get its factorial number;
Attaching the code for your reference.
function fact = factorial(n)
fact = 1; %base case, for F(0);
for i = 1:n %looping through values from 1 : n to multiply each value;
fact = fact*i; %multiplying with our previous values.
end
end
The fact will have your desired factorial of the integer you called function with.
1 Comment
More Answers (4)
ANSHU PRIYA
on 12 Jun 2021
okh so we are intresting in to finding the value of 7 factorial
programming:-
%calculation of factorial
n=7;
factvalue=1;
for i=1:7
factvalue=factvalue*i
end
3 Comments
ANSHU PRIYA
on 13 Jun 2021
its obvious !because the notation of factorial are denoted by n!
here we are finding the value of n! where n=7.
thats why we assinginf here n=7
Walter Roberson
on 13 Jun 2021
So if I coded
%calculation of factorial
n=7;
factvalue=1;
for i=1:9
factvalue=factvalue*i
end
then afterwards factvalue would hold n! = 7! ? Or would it hold 9! ? Where is the connection between the value of n and the value calculated?
Darya
on 15 Nov 2022
Edited: Walter Roberson
on 15 Nov 2022
n=input('n=')
if n>=0&&n==fix(n)
f=1;
for i=2:n
f=f*1;
end
else
disp('ererr')
end
f
1 Comment
Hugo
on 18 Oct 2023
hecho de función = factorial(n)
hecho = 1; % caso base, para F(0);
for i = 1:n %recorriendo valores de 1:n para multiplicar cada valor;
hecho = hecho*i; %multiplicando con nuestros valores anteriores.
fin
fin hecho = 1; % caso base, para F(0); for i = 1:n %recorriendo valores de 1:n para multiplicar cada valor; hecho = hecho*i; %multiplicando con nuestros valores anteriores. finfin
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